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diamong [38]
3 years ago
14

A photo is printed on an 13-inch by 15-inch piece of paper. The photo covers 143 square inches and has a uniform border. What is

the width of the border?
Mathematics
1 answer:
iVinArrow [24]3 years ago
4 0

Answer:

52 inches i think

Step-by-step explanation:

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Is (2,-1) a solution of 2x-y=5? Explain and solve please and thank you.
saul85 [17]

Answer:

YES

Step-by-step explanation:

2x-y=5

2(2)-(-1)=5

4-(-1)=5

4+1=5

5=5

3 0
3 years ago
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DO IT YES GOOOOD! END HIM ANAKIN
Luda [366]
The answer is A) 28
Set up a proportion based on the triangle side lengths. I chose to put the smaller ones over the bigger ones: 
\frac{6}{42} =  \frac{32-x}{x}
Then cross multiply to get 1344-42x = 6x
Add 42x to both sides to isolate the x changing the equation to 13444 = 48x
Divide both sides by 48 to get x = 28
5 0
3 years ago
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What strategy would use to divide 36 by 6 explain why you chose that strategy
wel
I would pick long division because you regroup and better understand
6 0
3 years ago
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Think about tossing two coins.
ankoles [38]

Given:

Two coins are tossed.

To find:

1. P(H on first coin)?

2. P(H on second coin)?

3. List the paired outcomes for tossing two coins.

4. How many ways are there for two coins to land?

5. What is P(HH)?

Solution:

If a a coin is tossed, then we have to possible outcomes, i.e., heads (H) and tails (T).

It is given that two coins are tossed.

1. The probability of getting a heads on first coin is:

P(H \text{ on first coin})=\dfrac{1}{2}

2. The probability of getting a heads on second coin is:

P(H \text{ on second coin})=\dfrac{1}{2}

3. If two coins are tossed, then the total possible outcomes are:

\{HH,HT,TH,TT\}

4. The number of ways for two coins to land is 4.

5. The probability of the heads on both tosses is:

P(HH)=\dfrac{1}{4}

Therefore, the required solution are:

1. P(H \text{ on first coin})=\dfrac{1}{2}

2. P(H \text{ on second coin})=\dfrac{1}{2}

3. List of possible outcomes is \{HH,HT,TH,TT\}.

4. Number of possible outcomes is 4.

5. P(HH)=\dfrac{1}{4}

5 0
3 years ago
RU and JM are diagonals. Given ST= 6, KL = 10, and RU= 12, find JM
AfilCa [17]

Your question is incomplete. The complete question is attached down

Answer:

JM = 20 units

Step-by-step explanation:

∵ Hexagon RSTUVW is similar to hexagon  JKLMNP

∴ The corresponding sides and diagonals have a constant ratio

∴ \frac{RS}{JK}=\frac{ST}{KL}=\frac{TU}{LM}=\frac{UV}{MN}=\frac{VW}{NP}=\frac{RW}{JP}=\frac{RU}{JM}

∵ ST = 6 units

∵ KL = 10

∴ \frac{ST}{KL}=\frac{6}{10}

- Simplify it by dividing up and down by 2

∴ \frac{ST}{KL}=\frac{3}{5}

∵ \frac{ST}{KL}=\frac{UR}{JM}

∵ RU = 12 units

∴  \frac{3}{5}=\frac{12}{JM}

- By using cross multiplication

∴ JM × 3 = 5 × 12

∴ 3 JM = 60

- Divide both sides by 3

∴ JM = 20 units

5 0
3 years ago
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