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nikitadnepr [17]
3 years ago
5

HELP FAST PLS QUICK!!!!

Mathematics
1 answer:
Maksim231197 [3]3 years ago
7 0

Answer:

\sqrt{2}

Step-by-step explanation:

we know that

tan^{2}(\theta)+1=sec^{2}(\theta)

we have

tan^{2}(\theta)=-1

substitute the value

(-1^{2})+1=sec^{2}(\theta)

(1)+1=sec^{2}(\theta)

sec^{2}(\theta)=2\\ \\sec(\theta)=(+/-)\sqrt{2}

Remember that

The angle theta belong to the III and IV quadrant, but the tangent is negative, therefore belong to the IV quadrant

so

sec(\theta) is positive

therefore

sec(\theta)=+\sqrt{2}

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