Given that we need to determine the radius of the circle.
<u>Radius:</u>
By definition of radius of circle, the radius is the length of the line which is drawn from the center of the circle to any point on the circle.
From the figure, we need to determine the radius of the circle.
As, we can see that, the distance from the center of the circle to the point on the circle is 11 cm.
Since, we know that, the radius is the distance from the center of the circle to the point on the circle then, the radius of the given circle is 11 cm
Thus, radius of the circle is 11 cm.
Answer:
See below.
Step-by-step explanation:
The rocket's flight is controlled by its initial velocity and the acceleration due to gravity.
The equation of motion is h(t) = ut + 1.2 g t^2 where u = initial velocity, g = acceleration due to gravity ( = - 32 ft s^-2) and t = the time.
(a) h(t) = 64t - 1/2*32 t^2
h(t) = 64t - 16t^2.
(b) The graph will be a parabola which opens downwards with a maximum at the point (2, 64) and x-intercepts at (0, 0) and (4, 0).
The y-axis is the height of the rocket and the x-axis gives the time.
Maximum height = 64 feet, Time to maximum height = 2 seconds, and time in the air = 4 seconds.
Answer:
Step-by-step explanation:
From the picture attached,
Statements Reasons
1). In ΔABC, DE intersects AB and AC 1). Given
2). DE║BC 2). Given
3). ∠ADE ≅ ABC 3). Corresponding angles postulate
4). ∠AED ≅ ∠ACB 4). Corresponding angles postulate
5). ΔADE ~ ΔABC 5). AA similarity postulate
6). 
6). Definition of two similar triangles
Hence proved.
Answer:
x ∈ {−0.766664695962, 2, 4}
Step-by-step explanation:
The equation is a combination of polynomial and exponential functions. There are no algebraic methods for solving such an equation. Graphical and iterative methods work nicely, though.
The attached graph shows integer solutions at x=2 and x=4. There is also an irrational negative solution near x = −0.766664695962. The latter was found by using Newton's method iteration on the graphical value of -0.767.
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