a)Factors of 6 = 1, 2, 3 and 6. Factors of 9 = 1, 3 and 9. Therefore, common factor of 6 and 9 = 1 and 3. Highest common factor (H.C.F) of 6 and 9 = 3.

he HCF of 68 is 68.....! bcoz 68 itself is a highest factor of 68.....!

48 are 2×2×2×2⇒16

b)64 = 1 × 2 × 2 × 2 × 2 × 2 × 2. 80 = 1 × 2 × 2 × 2 × 2 × 5.

Factors of 128 are 1, 2, 4, 8, 16, 32, 64, 128. There are 8 integers that are factors of 128. The greatest factor of 128 is 128. 3.

c.Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

54 = 2 × 27 = 2 × 3 × 9 = 2 × 3 × 3 × 3. 81 = 3 × 27 = 3 × 3× 9 = 3 × 3 × 3 × 3. 99 = 11 × 9 = 11 × 3 × 3. Factors common to all three numbers is 3 × 3.

8 0

3 years ago

How to do these problems

Paul [167]

So all you have to do is divide the fractions. you would write 7/15 in your calculator, and boom you have the answer. or, you can just divide it by pencil and paper, which is harder. 4/5=0.8

5 0

3 years ago