One side of a parallelogram has endpoints (3, 3) and (1, 7).. . What are the endpoints for the side opposite?. . . . (8, 1) and
2 answers:
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9514 1404 393
Answer:
x = 1 or 5
Step-by-step explanation:
The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...
Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.
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<em>Comment on "cross multiply"</em>
Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.
What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.
Answer:
a)
In order to find this probability we can use excel with the following code:
=GAMMA.DIST(40;5,8,TRUE)-GAMMA.DIST(1,5,8,TRUE)
And we got:
b)
In order to find this probability we can use excel with the following code:
=1-GAMMA.DIST(40,5,8,TRUE)
And we got:
Step-by-step explanation:
Previous concepts
The Gamma distribution "is a continuous, positive-only, unimodal distribution that encodes the time required for events to occur in a Poisson process with mean arrival time of
"
Solution to the problem
Let X the random variable that represent the lifetime for transistors
For this case we have the mean and the variance given. And we have defined the mean and variance like this:
(1)
(2)
From this we can solve and [/tex]\beta[/tex]
From the condition (1) we can solve for and we got:
(3)
And if we replace condition (3) into (2) we got:
And solving for
And now we can use condition (3) to find
So then we have the parameters for the Gamma distribution. On this case
Part a
For this case we want this probability:
In order to find this probability we can use excel with the following code:
=GAMMA.DIST(40;5,8,TRUE)-GAMMA.DIST(1,5,8,TRUE)
And we got:
Part b
For this case we want this probability:
In order to find this probability we can use excel with the following code:
=1-GAMMA.DIST(40,5,8,TRUE)
And we got: