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zlopas [31]
3 years ago
9

Simplify each expression 8+7y-3y+2-4

Mathematics
2 answers:
Kobotan [32]3 years ago
8 0

Answer:

6+4y

Step-by-step explanation:

Evgen [1.6K]3 years ago
3 0
Your answer i believe would be 6+4y
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Find the area and the circumference of a circle with radius 7 cm.
aniked [119]

Answer:

C=14pi cm

A=49pi cm^2

Step-by-step explanation:

1) Circumference of a circle is 2piR and R=7cm

C=2pi(7)

C=14pi cm

2) Area of a circle is piR^2 and R=7cm

A=pi (7)^2

A=49pi cm^2

3 0
3 years ago
The mean age of a student book club is 14.2 years. A 27-year-old teacher is invited to join the club. How does the teacher’s age
MAXImum [283]
The new mean age will be greater than 14.2 years because the teacher is older than the previous mean.
3 0
3 years ago
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How is the point (2, 9) in the scatterplot described?
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7 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST
vfiekz [6]

Answer:

The slope is 3/2 and the y intercept is 4

Step-by-step explanation:

We want to write in the form

y = mx+b where m is the slope and b is the y intercept

-3x+2y = 8

Add 3x to each side

-3x+3x+2y = 3x+8

2y = 3x+8

Divide each side by 2

2y/2 = 3x/2 + 8/2

y = 3/2x +4

The slope is 3/2 and the y intercept is 4

7 0
3 years ago
In a large population of adults, the mean IQ is 112 with a standard deviation of 20. Suppose 200 adults are randomly selected fo
Snezhnost [94]

Answer:

(c)approximately Normal, mean 112, standard deviation 1.414.

Step-by-step explanation:

To solve this problem, we have to understand the Central Limit Theorem

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

In this problem, we have that:

\mu = 112, \sigma = 20, n = 200

Using the Central Limit Theorem

The distribution of the sample mean IQ is approximately Normal.

With mean 112

With standard deviation s = \frac{20}{\sqrt{200}} = 1.414

So the correct answer is:

(c)approximately Normal, mean 112, standard deviation 1.414.

4 0
3 years ago
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