Answer:
100/9
Step-by-step explanation:
(7*5*2/7*3)² * (5^0/2^-3)³ * 2^-9
Solution:
We know that any number with power 0 = 1
(7*5*2/7*3)² * (1/2^-3)³ * 2^-9
Now cancel out 2 by 2
= (7*5*2/7*3)² * (1/1^-3)³ * 1^-9
=(70/21)² * (1)³/(1^-3)³ * 1^-9
=(10/3)^2 * 1/1^-1 * 1/1^9
=100/9 *1 *1
=100/9....
Answer:
And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613
Step-by-step explanation:
The estimated proportion of interest is 
We need to find a critical value for the confidence interval using the normla standard distributon. For this case we have 95% of confidence, then the significance level would be given by
and
. And the critical value is:
The confidence interval for the true population proportion is interest is given by this formula:
Replacing the values provided we got:
And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613
Answer:
y- intercept is (2;0)
Step-by-step explanation:
Then the x- intercept is (3;0)............
N^3 +4n^2 +8n -16
hope it help
mark me brainliest if i right ty
Answer:
3 to the power of 5 (I cant write as exponent)
Step-by-step explanation: