Ok so I’m thinking that s = 93 because first I multiply first sides of the equation by -4, which was s-61=32. Then I moved the constant to the right hand side and change its sign which will be s=32+61. After I did all of that I added the numbers together and got 93..... therefore s=93
Looks fishy to me, the way this problem combines <, = and > symbols.
But anyway. Subtract 3x from both sides. You'll get
5 < x = 2 > 0 2 > 0 is true, but that's a different type of math problem (true or false). If you decide to substitute '1' for 2 > 0, then the "1" says "TRUE."
Then 5 < x = true, so you must find x values that are larger than 5.
That would be (5, infinity)
Please go back and ensure that you have copied down the original problem exactly as it appears.
Im going to go on and say that it is 90
13/20 :) i can explain if you want me to :)
