Answer:
Pumping gas into take with greater rate of change.
Step-by-step explanation:
Rate of change is equal to change in number of gallons per minutes.
Here we have two case
Case 1: Filling swimming pool with 100 gallons of water in 15 minutes.
So, we find how many gallons fill in 1 minutes.


Case 2: Pumping 12 gallons of gas into tank in 3 minutes.
So, we find how many gallons fill in 1 minutes.


Rate of case 2 is greater than case 1.
Thus, Pumping gas into tank with greater rate of change.
Answer:
i think it might be the letter D
Answer:
A is A=2(1+2)a2
B is A≈208.18cm²
Step-by-step explanation:
A explanation is A=2(1+2)a2=2·(1+2)·102≈482.84271
B explanation is A=145(5+25)a2=14·5·(5+2·5)·112≈208.17777cm²
Answer:
a) Vertex is at (-3, -1)
b) y-intercept is at (0,8)
c) x intercept is at (-4,0) and (-2,0)
d) x=-3
Step-by-step explanation:
The vertex of a parabola is the lowest or highest point, implying that all points are reflected across it. It's the only y value that doesn't have a corresponding pair.
For example, -1 and 1, -3 and 3, and so on.
The vertex is at (-3,-1) because it is the sole point without a corresponding y value (-3,-1)
The y-intercept is where the parabola meets the y axis or when the x value equals 0. To determine the y-intercept, simply find when x = 0.
intercept y: (0,8)
The x-intercepts are the same as the y-intercepts; you must determine where the parabola crosses the x-axis or when y = 0.
x intercept 1:(-4,0)
x intercept 2: (-2,0)
The axis of symmetry is also the x coordinate of the vertex which is 3 so
x = 3
Given a function <em>g(x)</em>, its derivative, if it exists, is equal to the limit

The limit is some expression that is itself a function of <em>x</em>. Then the derivative of <em>g(x)</em> at <em>x</em> = 1 is obtained by just plugging <em>x</em> = 1. In other words, find <em>g'(x)</em> - and this can be done with or without taking a limit - then evaluate <em>g'</em> (1).
Alternatively, you can directly find the derivative at a point by computing the limit

But this is essentially the same as the first method, we're just replacing <em>x</em> with 1.
Yet another way is to compute the limit

but this is really the same limit with <em>h</em> = <em>x</em> - 1.
You do not compute <em>g</em> (1) first, because as you say, that's just a constant, so its derivative is zero. But you're not concerned with the derivative of some <em>number</em>, you care about the derivative of a function that depends on a <em>variable.</em>