3 years ago

Find three points of the linear equation -x-2y=-10

Mathematics

1 answer:

n200080 [17]3 years ago

6 0

We can find 3 points by plugging them in

x = -12 y = 1
x = 10 y = 0
x = 0 y = 5

You might be interested in

Perimeter is the distance around a figure or region.<br> a. true<br> b. false

makkiz [27]

A. True

The sum of the distances round the shape is the Perimeter.

3 0

3 years ago

Read 2 more answers

If 30g of sugar is needed to make 4 cakes how much grams of sugar is needed to make 7 cakes

arsen [322]

There's two ways to do this.

The first way:
Work out the amount of sugar needed to make one cake, and then multiply that by 7.

30 grams ÷ 4 cakes = 7.5 grams for 1 cake.
7.5 grams × 7 cakes = 52.5 grams for 7 cakes.

The second way:
Work out the ratio of sugar:cake by doing 7 ÷ 4, and then multiplying that value by 30.

7 cakes ÷ 4 cakes = 1.75
1.75 × 30 grams = 52.5 grams for 7 cakes.

Either way, the answer is 52.5 grams.

6 0

3 years ago

If x>2,then x2-x-6/x2-4=

statuscvo [17]

$\frac{x^2-x-6}{x^2-4}=(*)\\------------\\x^2-x-6=0\\a=1;\ b=-1;\ c=-6\\\Delta=b^2-4ac;\ \Delta=(-1)^2-4\cdot1\cdot(-6)=1+24=25\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\x_1=\frac{1-\sqrt{25}}{2\cdot1}=\frac{1-5}{2}=\frac{-4}{2}=-2\\\\x_2=\frac{1+\sqrt{25}}{2\cdot1}=\frac{1+5}{2}=\frac{6}{2}=3\\\\x^2-x-6=(x+2)(x-3)$
$---------------------\\x^2-4=x^2-2^2=(x-2)(x+2)\\-------------------\\\\(*)=\frac{(x+2)(x-3)}{(x-2)(x+2)}=\frac{x-3}{x-2}$

6 0

3 years ago

What is the meaning of gcf in math terms

Scorpion4ik [409]

Greatest common factor

7 0

3 years ago

What is the value of the expression 6( -5 1/4 ?

Norma-Jean [14]

Answer:

-63/2

Step-by-step explanation:

6( -5 1/4)

= 6(-21/4)

= -63/2

6 0

3 years ago