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IRINA_888 [86]
3 years ago
8

What’s 5 X 50 - 42 X 71

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
6 0
The answer for this is 2732
Mekhanik [1.2K]3 years ago
6 0

Answer:

-2732

Step-by-step explanation:

Follow the order of operations and perform multiplication first.

5*50=250

42*71=2982

250-2982=-2732

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Aleks04 [339]

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2 years ago
Can someone plz help me solved this problem! I need help ASAP! Will mark you as brainiest! Plz help
cupoosta [38]

Answer:

y>=2x-2

Step-by-step explanation:

You're gonna want to make one side equal to zero so subtract 8 from both sides

8x-4y-8 ≤0

Then you want to move the x and the constant back over by adding (-8x+8)

-4y ≤-8x+8

Then you'd flip the inequality sign and divide both sides by 4

y>=(8/4)x-(8/4)

Then you'd break the big numbers and make them exponents

y>=(2^3/2^2)x-(2^3/2^2)

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6 0
3 years ago
What is the sum of<br>5/13<br>11/13<br>and<br>10/13​
MrRissso [65]

Answer:

2

Step-by-step explanation:

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5 0
3 years ago
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What is/are the coefficient(s) in the expression below? 2x^2 + x - 15<br> PLEASE ANSWER MEE
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Consider the equation 256 = x4. How many real solutions of x exist?
svetoff [14.1K]
256 = x^{4}

By subtracting 256 and moving terms, we get:
x^{4} - 256 = 0
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This is a difference of two squares.
(x^{2} - 4)(x^{2} + 4) = 0
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We can see that for even powers, there will only lie two solutions, because they cannot lie less than zero. Any form of a quadratic will only have 2 solutions, because the remaining are all imaginary. For this example, we can see that, since the degree of the binomial is degree 4, there can only lie two solutions because the conjugate is also a solution.

For any quadratic or even degree functions, the conjugate solution has to be rejected for the equation to satisfy the laws of squares and square roots.

Thus, the remaining 2 solutions are imaginary, leaving only two real solutions.
4 0
3 years ago
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