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3 years ago

15

If you understand, please help me

1 answer:

erik [133]3 years ago

4 0

The answer would be 19

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Steve had 48 chocolates but decided to give 8 chocolates to each of his coworkers,

Lunna [17]

Answer:

48 - 8c

Step-by-step explanation:

let c be the number of coworkers

48 - 8c would be the expression because it starts with 48 and for every coworker 8 is subtracted.

5 0

3 years ago

Read 2 more answers

How do I find the inverse of this problem?

raketka [301]

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Inverse of real function.

Let's consider here, g(n) = y ,

so we get as,

$y = \sqrt[3]{ \frac{n - 1}{2} }$

no, cubing the power both side we get as,

=>

${y}^{3} = \frac{n - 1}{2}$

now,

$2 {y}^{3} = n - 1$

so finally, we get as,

=>

$n = 2 {y}^{3} + 1$

hence,here, n = inverse of the g(n) function.

so,

g^-1 (n) = 2y^3+1.

7 0

3 years ago

Suppose j varies jointly with g and v, and j=1 when g=4 and v=5. what is j when g=10 and v=9?

Tems11 [23]

J $\alpha gv$
j=agv where a is a constant of proportionality.
j=1 when g=4 and v=5
1=a*4*5
1=20a
a=1/20
a= 0.05
j=0.05gv
When g=10 and v=9,
j=0.05*10*9
j=0.5*9
j=4.5

4 0

3 years ago

You have been asked to design a can shaped like right circular cylinder that can hold a volume of 432π-cm3. What dimensions of t

rosijanka [135]

Answer:

$Height = 12cm$

$Radius = 6cm$

Step-by-step explanation:

Given

Represent volume with v, height with h and radius with r

$V = 432\pi$

Required

Determine the values of h and r that uses the least amount of material

Volume is calculated as:

$V = \pi r^2h\\$

Substitute 432π for V

$432\pi = \pi r^2h$

Divide through by π

$432 = r^2h$

Make h the subject:

$h = \frac{432}{r^2}$

Surface Area (A) of a cylinder is calculated as thus:

$A=2\pi rh+2\pi r^2$

Substitute $\frac{432}{r^2}$ for h in $A=2\pi rh+2\pi r^2$

$A=2\pi r(\frac{432}{r^2})+2\pi r^2$

$A=2\pi (\frac{432}{r})+2\pi r^2$

Factorize:

$A=2\pi (\frac{432}{r} + r^2)$

To minimize, we have to differentiate both sides and set $A' = 0$

$A'=2\pi (-\frac{432}{r^2} + 2r)$

Set $A' = 0$

$0=2\pi (-\frac{432}{r^2} + 2r)$

Divide through by $2\pi$

$0= -\frac{432}{r^2} + 2r$

$\frac{432}{r^2} = 2r$

Cross Multiply

$2r * r^2 = 432$

$2r^3 = 432$

Divide through by 2

$r^3 = 216$

Take cube roots of both sides

$r = \sqrt[3]{216}$

$r = 6$

Recall that:

$h = \frac{432}{r^2}$

$h = \frac{432}{6^2}$

$h = \frac{432}{36}$

$h = 12$

Hence, the dimension that requires the least amount of material is when

$Height = 12cm$

$Radius = 6cm$

3 0

3 years ago

Writing the missing numbers

Xelga [282]

You cant see it clearly

8 0

3 years ago