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matrenka [14]
3 years ago
6

Change this equation to the form y= (slope) x+y-intercept -6x+2y=4

Mathematics
1 answer:
weeeeeb [17]3 years ago
6 0

Hello!

The slope-intercept form is the form of y = mx + b.

-6x + 2y = 4 is not yet in the slope-intercept form.

4 = -6x +2y

-2y = -6x -4

2y = 6x + 4

y = 3x + 2 is the slope-intercept form of the equation.

I hope this helps you! Have a lovely day!

- Mal

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Plot 5 parabolas, one through each set of color-coordinated points. (image attached)
Ahat [919]

Answer:

Red: y=(x+6)^2-1

Blue: y=-(x+3)^2+1

Green: y=(x^2-1)

Orange: y=-(x-3)^2+1

Purple: y=(x-6)^2-1

Step-by-step explanation:

Use Desmos to check

8 0
3 years ago
A toll bridge charges $1.00 for passenger cars and $2.25 for other vehicles. Suppose that during daytime hours, 60% of all vehic
lora16 [44]

Answer:

Total revenue = 13.5 + 9 = $22.5

Step-by-step explanation:

The toll charges $1.00 for passenger cars and $2.25 for other vehicles. During daytime hours  60% of all the vehicles are passenger vehicles.

A particular daytime period 15 vehicle crossed the bridge. Recall that during daytime period, 60% of all the vehicles are passenger vehicles . Therefore,

Passenger vehicles = 60% of 15

Passenger vehicles = 60/100 × 15

Passenger vehicles = 900/100

Passenger vehicles = 9

9 of the vehicles are passenger vehicle and the charges for passenger cars is $1.00. other vehicle is $2.25.

revenue for passenger cars = 1 × 9 = $9

revenue for other vehicles = 2.25 × 6 = $13.5

Total revenue = 13.5 + 9 = $22.5

8 0
3 years ago
PLEASE HELP
Lera25 [3.4K]

Answer:

To construct the Square using a compass and straight edge, you have written the steps not in proper order. I am rearranging the steps for you

1. Construct horizontal ​ H J¯¯¯¯¯

2. ​Construct a circle with point H as the center and a circle with point J as a center with each circle having radius HJ .

3.Label the point of intersection of the two circles above​ ​ HJ¯¯¯¯¯ ​​, point K, and the point of intersection of the two circles below ​ HJ¯¯¯¯¯ ​, point L.

4.Construct KL¯¯¯¯¯ , the perpendicular bisector of ​ HJ¯¯¯¯¯ ​, intersecting​ ​ HJ¯¯¯¯¯ ​ ​​at point M.

5.Construct a circle with point M as the center with radius MJ .

6.Label the point of intersection of circle M and ​ KL¯¯¯¯¯ ​ closest to point K, point N, and the point of intersection of circle M and ​ KL¯¯¯¯¯ ​  closest to point L, point O.

7.Construct HN¯¯¯¯¯¯ , NJ¯¯¯¯¯ , JO¯¯¯¯¯ , and OH¯¯¯¯¯¯ to complete square HNJO .





3 0
3 years ago
What is the geometric mean of 4 and 10
GalinKa [24]

Answer: 6.3

Step-by-step explanation:

The formula for geometric mean is given as :

G.m = \sqrt{pq}

Therefore , the geometric mean between 4 and 10 will be :

G.m = \sqrt{4(10)}

      = \sqrt{40}

      = 2\sqrt{10}

     = 6.3

8 0
3 years ago
Find the 6th term of the arithmetic sequence X – 9, -X – 11, -3.3 – 13, ...
MrMuchimi

Answer:

-13x-23

Step-by-step explanation:

Given sequence:  x-9, -x-11, -3x-13

Therefore,

  • a_1=x-9
  • a_2=-x-11
  • a_3=-3x-13

General form of an arithmetic sequence: a_n=a+(n-1)d

(where a is the first term and d is the common difference)

To find the common difference, subtract a term from the next term:

\begin{aligned}d & =a_2-a_1\\ & =(-x-11)-(x-9)\\ & = -x-11-x+9\\ & = -2x-2\end{aligned}

Therefore,

a_n & =(x-9)+(n-1)(-2x-2)

To find the 6th term, input n = 6 into the equation:

\begin{aligned}\implies a_6 & =(x-9)+(6-1)(-2x-2)\\ & = (x-9)+7(-2x-2)\\ & = x-9-14x-14\\ & = -13x-23\end{aligned}

3 0
2 years ago
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