Answer:
1%
Step-by-step explanation:
Given : You have used the significant level of 0.01 to estimate the average hours of television viewing for the NJ students.
To Find :What is the chance that our interval estimate does not contain the true population mean?
Solution:
We are given that You have used the significant level of 0.01 to estimate the average hours of television viewing for the NJ students.
So, α=0.01
Significance level indicates a risk of concluding that a difference exists when there is no actual difference.
So, The chance that our interval estimate does not contain the true population mean is 0.01
So, The chance that our interval estimate does not contain the true population mean is 
Hence Option D is true
Answer:
nope u took my points so im not helping
Answer:
Interval of 50 on both axis
Step-by-step explanation:
Given





There are several ways to do this, but I will use the observation method, since the dataset is small.
Considering the x-coordinates

Each element of the data set is a multiple of 50.
Hence, an interval of 50 can be used on the x-axis
Considering the y-coordinates

Each element of the data set is a multiple of 50.
Hence, an interval of 50 can be used on the y-axis
<em>So, an interval of 50 can be used on both axes</em>
Answer:
<u>D.</u> <u>126</u>
Step-by-step explanation:
30 ÷ 5 = 6
5 * 6 = 30
6 * 6 = 36
10 * 6 = 60
60 + 30 + 36 = <u>126</u>
A is the answer probably but not too sure