Vertex=(-1,0)
x^2-2x-1
y=− ( x + 1 )^2 + 0
Use the vertex form, y=a(x−h)^2+k, to determine the values of a, h, and k.
Find the vertex (h,k) = (-1,0)
Answer:
the answer is G) Change 30 to 3,000
Answer:
![y + 3 = -1\frac{3}{5}[x - 2]\:or\:y - 5 = -1\frac{3}{5}[x + 3]](https://tex.z-dn.net/?f=y%20%2B%203%20%3D%20-1%5Cfrac%7B3%7D%7B5%7D%5Bx%20-%202%5D%5C%3Aor%5C%3Ay%20-%205%20%3D%20-1%5Cfrac%7B3%7D%7B5%7D%5Bx%20%2B%203%5D)
Step-by-step explanation:
First, find the <em>rate of</em><em> </em><em>change</em><em> </em>[<em>slope</em>]:
Now input the slope into the Point-Slope Formula. In this formula, all negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT signs:
![y - y_1 = m[x - x_1]](https://tex.z-dn.net/?f=y%20-%20y_1%20%3D%20m%5Bx%20-%20x_1%5D)
I am joyous to assist you anytime.
The best statement that describes the angle JKL is inscribed angle.
<h3>What is an inscribed angle?</h3>
An inscribed angle in a circle is formed by two chords that have a common end point on the circle. The chord JK and LK intersect in the circle.
The angle ∠JKL is not an obtuse angle because it's less than 90 degrees.
The angle ∠JKL is not a vertical angle because it's not vertically opposite any angle.
The angle ∠JKL is not a central angle because it was not from from the centre of the circle.
The angle is an inscribed angle because it was formed by the intersection of two chords in the circle.
learn more on angles here: brainly.com/question/6563602
#SPJ1
