If you use the equation y-y1=m(x-x1) it would give you y-0=-1/4(x-2) which you would then have to simplify into slope intercept from rather than point slope form.
you do this by using the distributive property on the -1/4(x-2) which would give you y=-1/4x+1/2
Due to length restrictions, we kindly invite to see the explanation below to know the answer with respect to each component of the question concerning linear equations.
<h3>How to determine a linear equation describing the daily distance of a runner</h3>
In this question we need to derive an expression of the <em>daily</em> distance as a function of time. Now we proceed to complete the components:
- <em>Linear</em> equations have an <em>independent</em> variable (t - time) and a dependent variable (x - daily distance).
- We notice that the daily distance increases linearly in time, then then we have the following pattern:
t 1 2 3 4 5 6
x 2 2.5 3 3.5 4 4.5 - The equation that represents the n-th term of the sequence is x(n) = 2 + 0.5 · (n - 1).
- The week when Susie will run 10 miles per day is:
10 = 2 + 0.5 · (n - 1)
8 = 0.5 · (n - 1)
n - 1 = 16
n = 17
Susie will run 10 miles per day in the 17th week. - It is not reasonable to think that pattern will continue indefinitely as it is witnessed in the difficulties experimented by <em>fastest</em> runners in the world to increase their <em>peak</em> speeds.
- A marathon has a distance of 26 miles, then we must solve the following equation:
26 = 2 + 0.5 · (n - 1)
24 = 0.5 · (n - 1)
48 = n - 1
n = 49
Susie should start her training 49 weeks before the marathon.
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Answer:
When you are adding or subtracting a negative fraction, you usually want to consider the numerator as negative. The method is just the same, except now you may need to add negative or positive numerators. Example 1: ... To add the fractions with unlike denominators, rename the fractions with a common denominator.
Step-by-step explanation:
<em>I GOT YOU!!!!</em>
Answer:
the last one
Step-by-step explanation:
function is: a relation from a set of inputs to a set of possible outputs where each input (X)is related to exactly one output (Y). Only the last choice satisfies this definition