3 years ago

Solve sin x + 2 sin x cos x = 0 for 0°

Mathematics

1 answer:

mr Goodwill [35]3 years ago

7 0

Answer:

0.04737184905

Step-by-step explanation:

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Step-by-step explanation:

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goldfiish [28.3K]

Answer:

$v=\sqrt{\dfrac{H\times 2gx}{m}+u^2}$

Step-by-step explanation:

The given formula is :

$H=\dfrac{m(v^2-u^2)}{2gx}$

We need to find the formula for v.

Cross multiplying the given formula.

$H\times 2gx=m(v^2-u^2)$

Dividing both sides by m. So,

$\dfrac{H\times 2gx}{m}=\dfrac{m(v^2-u^2)}{m}\\\\(v^2-u^2)=\dfrac{H\times 2gx}{m}$

Adding both sides by u².

$(v^2-u^2)+u^2=\dfrac{H\times 2gx}{m}+u^2\\\\v^2=\dfrac{H\times 2gx}{m}+u^2\\\\\text{So},\\\\v=\sqrt{\dfrac{H\times 2gx}{m}+u^2}$

Hence, this is the required formula.

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Step-by-step explanation:

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