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2 years ago

Which of these groups is in ascending order?

Mathematics

1 answer:

DochEvi [55]2 years ago

8 0

Answer:

I am think is the answer is A

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What is the value of k?

sammy [17]

Answer:

I think the answer is 2.. I'm sorry if its incorrect.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A pilot took 1/2 hours to complete his 1/3 pf his ttip how much longer will it take him to complete his trip?

Norma-Jean [14]

Answer:

1.5 hours

Step-by-step explanation:

1/2 + 1/2 + 1/2 =1.5

7 0

2 years ago

Jai bought 2 pounds of grapes for $2.49 per pound and 3 muffins for $ .75 per muffin. How much did he pay for the grapes and muf

natka813 [3]

Answer:

$7.23

Step-by-step explanation:

(2 x 2.49) + (3 x .75) = 4.98 + 2.25 = $7.23

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2 years ago

Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

2 years ago

Let f(x) represent the linear parent function.

Airida [17]

Answer:

left lexis line drag ang the answer

6 0

2 years ago