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Sever21 [200]
2 years ago
7

Which of these groups is in ascending order?

Mathematics
1 answer:
DochEvi [55]2 years ago
8 0

Answer:

I am think is the answer is A

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2. Factorizar: 3ax – 3ay – 2bx + 2by<br>help please :(
nekit [7.7K]

Answer:

There are no like terms.

Step-by-step explanation:

basically that is your answer you can not solve so it will be 3ax – 3ay – 2bx + 2by

7 0
2 years ago
What additional information would you need to prove by the HL theorem?
Butoxors [25]

Answer:

<em>Answer:</em> <em>A</em>   \overline{TM}\cong \overline{OR}

Step-by-step explanation:

The HL Theorem states that if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent.

Triangles TRO and OMT share the hypotenuse, so the first part of the theorem is met.

Both triangles are right because they have an internal angle of 90°, so the second condition is also met.

Since there is no indication of any leg to be congruent to another leg, we need additional information to prove that both triangles are congruent.

One of these two conditions should be met:

Side TM is congruent to side OR, or

Side MO is congruent to side RT.

From the available options, only the first is correct.

Answer: A \mathbf{\overline{TM}\cong \overline{OR}}

8 0
2 years ago
HELP ME PLSS.....
Tamiku [17]

Answer:

2.5 f

Step-by-step explanation:

5

F x —

2

5

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2

I hope it's help :)

5 0
2 years ago
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At the airport, there is a moving walkaway 500 meters long, which moves at a speed of 4 km/hour. Aditya and Ravi step on the wal
Nutka1998 [239]

Answer:

He is approximately 166.6 m ahead of Ravi.

If it's right please mark BRAINLIEST

3 0
2 years ago
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The graph of y=x^2 -7x+ 12 is a parabola with x-intercepts at
vesna_86 [32]

Answer:

<h2>x = 3 and x = 4 → (3, 0) and (4, 0)</h2>

Step-by-step explanation:

\text{x-intercept is for y = 0}.\\\\\text{We have the function:}\ y=x^2-7x+12.\\\\\text{Put y = 0 and calculate the value(s) of x.}\\\\x^2-7x+12=0\\\\x^2-3x-4x+12=0\\\\x(x-3)-4(x-3)=0\\\\(x-3)(x-4)=0\iff x-3=0\ \vee\ x-4=0\\\\x-3=0\qquad\text{add 3 to both sides}\\\boxed{x=3}\\\\x-4=0\qquad\text{add 4 to both sides}\\\boxed{x=4}

6 0
3 years ago
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