Answer:
°Draws attention to the magnitude and importance of threatened biodiversity.
°Identifies and documents those species most in need of conservation action.
°Provides an index of the decline of biodiversity.
Establishes a baseline from which to monitor the future °status of species.
Prokaryotic cells do not have membrane bound organelles and eukaryotic cells do have membrane bound organelles
Answer:
50% or 1/2. The result remains unchanged if the husband were to have G6PD.
Explanation:
For X-linked recessive inheritance, a female (XX) needs two recessive alleles to be affected while a male needs only one (XY). It is hypothetically assumed that the Y chromosome does not carry any trait.
Assuming the allele for the disease is represented by g, a woman whose father suffered from G6PD is a carrier for the disease with genotype 
. A normal man will have the genotype 
. When the 2 marries:
x = 
It thus means that 50% or 1/2 of their sons will be expected to have G6PD.
Now, assuming the husband has G6PD, the mating becomes:
x 
= 
50% or 1/2 of their sons is still expected to have G6PD. The ratio remains unchanged.
Answer:
Dominant sporophyte generation and microscopic gametophyte within sporophyte.
Explanation:
The sporophyte is the dominant generation, but multicellular male and female gametophytes which are microscopic in nature with the female gametophyte made up of few cells being buried in the tissues of the sporophyte and the male gametophyte, the pollen grain, being carried from plant to plant by wind, water, or animals. these are all produced within the flowers of the sporophyte.
Answer:
AUG
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Explanation:
