A^2 + B^2 = C^2
6^2 + B^2 = 7^2
36 + B^2 = 49
B^2 = 13
B = 3.61
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The one near the five is in the hundreds place and the one near the 4 is in the tenth place.
Feel free to message me if you need help on another problem.
<span>
-4c - 11 = 4c +21 add 4c to both sides
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<span>
-4c - 11 + 4c = 4c + 21 + 4c simplify
- 11 = 8c + 21</span> <span> subtract 21 from both sides
- 11 - 21 = 8c + 21 - 21 </span><span>simplify
- 32 = 8c divide both sides by 8
c = - 4That's it
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I hope you got
the idea
Answer:
Data set 3 has the highest IQR, so the correct option is {13,17,12,21, 18,20}
Step-by-step explanation:
The question is:
Which data set has the greatest spread for the middle 50% of its data
We have given the data sets:
{18,13,22, 17, 21, 24}
{17,19,22,26,17,14}
{13,17,12,21, 18,20}
{18,21,16,22,24,15}
To find the greatest spread for the middle we need to find the IQR for all the data sets and check which one is highest.
So,
For the first set: 22-17 = 5
For the second: 22-17 = 5
For the third set = 20-13 = 7
For the fourth set = 22-16 = 6
Since data set 3 has the highest IQR, so the correct option is {13,17,12,21, 18,20} ....
I don't know, this is tricky
