You share only one distribution, so we'll focus on that one: mean: 30; std. dev.: 4.
Draw a "standard normal curve." Draw a vertical line in the exact middle of your curve. Label this line "30." Now "one standard dev. above the mean" is 30+4=34; "two std. devs. above the mean is 30+4+4=38, or 30+8=38. "three std. devs. above the mean is 30+3(4) = 42.
Now work in the other direction. Start with the mean: 30. But now subtract the std. dev. (4) instead of adding it. You'll get 30-4=26. This is "1 std. dev. below the mean. Continue: find 2 and 3 std. devs. below the mean.
Answer:
x=20
Step-by-step explanation:
First, find LJ
Angle L = 60 (180 - 30 - 90)
The cosine of an angle is equal to the ratio of the adjacent side to the hypotenuse.
cos(L)=adj/hyp
cos(60)=LJ/40√2
LJ = cos(60)*40√2
LJ = 20√2
Now you can use LJ to find x. You also know the value of each angle, 45
x=20√2⋅cos(45)
x=20
If you are looking for g then the answer is g<34
Answer: x1=1 x2=-2 and x3=2
Step-by-step explanation:
1st x1=1 is 1 of the roots , so
F(1)=1-1-4+4=0 - true
So lets divide x^3-x^2-4x+4 by (x-x1), i.e (x^3-x^2-4x+4) /(x-1)=(x^2-4)
x^2-4 can be factorized as (x-2)*(x+2)
So x^3-x^2-4x+4=(x-1)*(x^2-4)=(x-1)(x-2)*(x+2)
So there are 3 dofferent roots:
x1=1 x2=-2 and x3=2
Answer:Answer:
60/11 or 5 5/11
Step-by-step explanation: Change to mixed numbers- 15/2 and 11/8.
multiply 15/2 by reciprocal- 15/2 x 8/11.
simplify-60/11
