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taurus [48]
3 years ago
5

In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro

m a sample of 81 business students over a one-week period. Assume the population standard deviation is 1.2 hours. The standard error of the mean is_______.
a. 7.5
b. 0.014
c. 0.160
d. 0.133
Mathematics
1 answer:
Ksju [112]3 years ago
7 0

Answer:

d. 0.133

Step-by-step explanation:

-Standard error is  calculated using the formula:

E=\frac{\sigma}{\sqrt{n}}\\\\\sigma-=standard \ deviation\\n=sample \ size

#We substitute the given values in the formula to solve for E:

E=\frac{\sigma}{\sqrt{n}}\\\\=\frac{1.2}{\sqrt{81}}\\\\=0.133

Hence, the standard error is 0.133 and the correct option is d

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-16 - (-t) = -45 how do you solve this please help​
zzz [600]

Answer:

- 29

Step-by-step explanation:

Step 1:

- 16 - ( - t ) = - 45       Equation

Step 2:

- 16 + t = - 45      Open Parenthises

Step 3:

t = - 45 + 16      Add 16 on both siddes

Answer:

t = - 29

Hope This Helps :)

8 0
4 years ago
Read 2 more answers
12. Write the equation of the line passing through the point (2,6) with slope 4 in
stepladder [879]

Answer:

y = 4x - 2

Step-by-step explanation:

slope = 4

y -6 = 4 ( x- 2 )

distribute the 4 to ( x - 2 )

y - 6 = 4x - 8

add 6 to both side

y = 4x - 2

Hopefully this helps you understand this concept.

5 0
4 years ago
Two trains travel at right angles to each other after leaving the same train station at the same time. Two hours later they are
hjlf

Answer:1547.9 miles per hour

Step-by-step explanation:

Let the two trains leave in x direction and y direction

Velocity of train in x direction be v

therefore velocity of train in Y direction is v+29

because one train is 29 miles per hour slower than other.

Distance travel by train in x direction is(x) v(2)

Distance travel by train in y direction is(y) 2(v+29)

distance between them after 2 hours is 4420 miles

Now using pythagoras theorem

x^2+y^2=\left ( 4420\right )^2

\left ( 2v\right )^2+\left ( 2\left ( v+29\right )\right )^2=\left ( 4420\right )

on solving

2v^2+58v-4881699=0

v=\frac{-58\pm \sqrt{\left ( 58 \right )^2+4\cdot 2\cdot4881699}}{2\cdot 2}

v=1547.889 miles per hour

7 0
3 years ago
What is the degree of the polynomial in the expression below?
Gelneren [198K]
In order to know the degree of the polynomial of a given expression, look for the variable having the largest exponent. So in the given polynomial above, the largest exponent is 8. Therefore, the polynomial has a degree of 8. So the answer would be option C. Hope this answer helps. 
7 0
4 years ago
Read 2 more answers
HELPPPPP PLEASEEEEEE !!​
geniusboy [140]

rotation, then translation, then reflection

5 0
3 years ago
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