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alex41 [277]
3 years ago
8

72 ivy sterms for 18 cenerpieces when she arrives at the venue, she realizes she will need 16 centerpieces. How many ivy sterms

should she use so that the ratio of ivy stems to centerpieces stays the same
Mathematics
1 answer:
amm18123 years ago
5 0

Answer:

64

Step-by-step explanation:

The ratio of ivy stems to centerpieces is 4:1. 18 goes into 72, 4 times. So if only 16 are needed then it would be 64. 16 x 4 = 64

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The distance traveled by a car at a constant rate is proportional to the time spent driving. In the equation d = 45t, d represen
OverLord2011 [107]
The constant of proportionality should be 45 miles per hour, and the car should travel 135 miles in three hours.
8 0
3 years ago
Consider the expression 25 – 10 ÷ 2 + 3.
Tems11 [23]

Given:

The expression is:

25-10\div 2+3

To find:

Part A: The expression using parentheses so that the expression equals 23.

Part B: The expression using parentheses so that the expression equals 3.

Solution:

Part A:

In option A,

(25-10)\div 2+3=15\div 2+3

(25-10)\div 2+3=7.5+3                       [Using BODMAS]

(25-10)\div 2+3=10.5

In option B,

25-10\div (2+3)=25-10\div 5

25-10\div (2+3)=25-2                      [Using BODMAS]

25-10\div (2+3)=23

In option C,

(25-10)\div (2+3)=15\div 5

(25-10)\div (2+3)=3

In option D,

25-(10\div 2)+3=25-5+3

25-(10\div 2)+3=28-5                     [Using BODMAS]

25-(10\div 2)+3=23

After the calculation, we have 25-10\div (2+3)=23 and 25-(10\div 2)+3=23.

Therefore, the correct options are B and D.

Part B: From part A, it is clear that

(25-10)\div (2+3)=3

Therefore, the correct option is C.

8 0
2 years ago
What is f(–3) for f(x) = 2x2 – x + 5?<br> A) 11 <br> B) 17 <br> C) 20 <br> D) 26
nirvana33 [79]

Answer: D

<u>Step-by-step explanation:</u>

f(x) = 2x² - x + 5

f(-3) = 2(-3)² - (-3) + 5

      = 2(9) + 3 + 5

      = 18 + 3 + 5

      = 26

6 0
3 years ago
Vx-w=2 <br> rearrange it and make x the subject
Anit [1.1K]

Answer:

vx - w = 2 \\ vx = 2 + w \\  x =  \frac{2 + w}{v}

8 0
2 years ago
The longer leg of a right triangle is 6cm longer than the shorter leg and also 1cm longer than the hyptenese. find the perimeter
CaHeK987 [17]
X - a leg  (x > 6);
x - 6 - a leg;
x + 1 - a <span>hypotenuse;</span>
Use the Pythagorean theorem
(x+1)^2=x^2+(x-6)^2

Use:(a\pm b)^2=a^2\pm2ab+b^2

x^2+2x+1=x^2+x^2-12x+36\ \ \ |-x^2-2x-1\\\\x^2-14x+35=0\ \ \ |-35\\\\x^2-14x=-35\\\\x^2-2\cdot x\cdot7=-35\ \ \ |+7^2\\\\x^2-2\cdot x\cdot7+7^2=-35+7^2\\\\(x-7)^2=14\iff x-7=\pm\sqrt{14}\ \ \ |+7\\\\x=7-\sqrt{14} < 6;\ x=7+\sqrt{14}

x=7+\sqrt{14}\\x-6=1+\sqrt{14}\\x+1=8+\sqrt{14}

The perimeter:

7+\sqrt{14}+1+\sqrt{14}+8+\sqrt{14}=16+3\sqrt{14}
5 0
3 years ago
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