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Luda [366]
3 years ago
6

An above-ground swimming pool in the shape of a cylinder has a diameter of 18 feet and a height of 4.5 feet. If the pool is fill

ed with water to 6 inches from the top of the pool, what is the volume, to the nearest cubic foot, of the water in the pool?⇆
Mathematics
2 answers:
KATRIN_1 [288]3 years ago
8 0

Answer:

the correct answer is the V = 1144.53

Step-by-step explanation:

This is the answer because you use the formula V = π*r^2*h

And you get 1144.53

laila [671]3 years ago
7 0

The volume of a cylinder is

                                   (pi) (radius²) (height) .

Radius = 1/2 diameter.
Radius of this pool = (1/2) (18 ft) = 9 ft

The pool is a cylinder with height of 4.5 feet. 
The water in it is also a cylinder, but only 4 ft high.

Volume of the water =

             (pi) x (radius²) x (height)

         =  (pi)  x  (9 ft)²  x  (4 ft)

         =  (pi)  x  (81 ft²)  x  (4 ft)

         =  (pi)  x  (324 ft³)  =  1,017.9 ft³ .

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Hi there! :)

Answer:

\huge\boxed{n = -2}

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Solve for n:

Add 3n to both sides:

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Answer:


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5 0
3 years ago
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Semenov [28]
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Since it is asking for the sum of the numbers you are adding.
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530,000 + 38,000 
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