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3 years ago

Please help as soon as possible

Mathematics

2 answers:

scZoUnD [109]3 years ago

6 0

Answer:

26.28

Step-by-step explanation:

First, add the side lengths of what you know. 6 + 6 + 8 = 20.

Then, find the circumference of the circle, BUT make sure you divide it by 2 because it is a semicircle in the figure.

The formula is 2 $\pi$ r, so plug in the radius = 2

So the circumference is 4 $\pi$ , then divide by 2 to get 2

20 + 2 $\pi$ = 26.28

slega [8]3 years ago

4 0

Step-by-step explanation:

we know all 3 values of trapezium length. so let's find out the circumference of half circle

circumference of circle= 2pi r

circumference of half circle = (180/360)× 2pi r

therefore it's equal to pi r

circumference = 22/7 ×2 (diameter is 4 so radius is 2)

circumference of half circle = 44/7

Total perimeter of the figure= 8+6+6+(44/7)

=20 + 6.28

= 26.28

Round of to nearest tenth place = 26.3

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3 years ago

Y=-x^2+2x+10 y=x+2 Substitution Need ASAP

aniked [119]

Answer:

$x_1=\frac{1+\sqrt{33} }{2},y_1=\frac{5+\sqrt{33} }{2}\\ \\ x_2=\frac{1-\sqrt{33} }{2},y_2=\frac{5-\sqrt{33} }{2}$

Explanation:

You must find the solution of the system using the substitution method.

System:

$y=-x^2+2x+10\\\\ y=x+2$

Substitute x+2 for y:

$x+2=y=-x^2+2x+10$

Pass all the terms to one side:

$x^2-2x+x+2-10\\ \\ x^2-x-8=0$

Use the quadratic formula to solve:

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}\\ \\ x=\frac{-(-1)+/-\sqrt{(-1)^2-4(1)(-8)} }{2(1)}\\ \\ x=\frac{1+/-\sqrt{1+32} }{2}$

$x_1=\frac{1+\sqrt{33} }{2}\\ \\x_2=\frac{1-\sqrt{33} }{2}$

Use y = x + 2 to find the value of y:

$y_1=2+x_1=2+\frac{1+\sqrt{33} }{2}\\ \\y_1=\frac{5+\sqrt{33} }{2} \\\\y_2=2+x_2=2+\frac{1-\sqrt{33} }{2}\\ \\ y_2=\frac{5-\sqrt{33} }{2}$

6 0

3 years ago

In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro

VladimirAG [237]

Answer:

Margin of error for a 95% of confidence intervals is 0.261

Step-by-step explanation:

Step1:-

Sample n = 81 business students over a one-week period.

Given the population standard deviation is 1.2 hours

Confidence level of significance = 0.95

Zₐ = 1.96

Margin of error (M.E) = $\frac{Z_{\alpha }S.D }{\sqrt{n} }$

Given n=81 , σ =1.2 and Zₐ = 1.96

Step2:-

 $Margin of error (M.E) = \frac{Z_{\alpha }S.D }{\sqrt{n} }$ 

 $Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }$ 

On calculating , we get

Margin of error = 0.261

Conclusion:-

Margin of error for a 95% of confidence intervals is 0.261

4 0

4 years ago