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gavmur [86]
3 years ago
10

Can you show me how you got that answer??...

Mathematics
1 answer:
Bess [88]3 years ago
4 0
What answer my dude.....
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A recent survey determined the IQ score of a random selection of residents of Alaska. The accompanying relative frequency distri
ycow [4]

Answer:

The class width is 20

Step-by-step explanation:

In a frequency or a relative frequency distribution the class width is calculated as the difference between the lower or upper class limits of consecutive classes. A point to note is that all the categories or classes usually have the same class width.

We use the first two classes to calculate the class width by using their respective upper limits;

Class width = 89 - 69

Class width = 20

4 0
3 years ago
Find the area of the shaded region round to the nearest tenth
Alenkinab [10]

Answer: 818.4

Step-by-step explanation:

Using the area of a sector formula, we get the area of the entire sector is (\pi)(27.8^{2})\left(\frac{150}{360} \right).

Using the formula A=\frac{1}{2} ab \sin C, we get the area of the triangle is \frac{1}{2}(27.8)(27.8)(\sin 150^{\circ}).

So, the area of the shaded sector is (\pi)(27.8^{2})\left(\frac{150}{360} \right)-\frac{1}{2}(27.8)(27.8)(\sin 150^{\circ}) \approx \boxed{818.4}

6 0
2 years ago
Help PLEASE THE LINK IS DOWN BELOW I TIMES
Mamont248 [21]
The answer is A because its simple reading. Are you 4? Because this is easy smh
3 0
3 years ago
Please help me with this. thank you. :)
Vinvika [58]

Answer:

11,550

Step-by-step explanation:

1200- 675( because its descending) + 250 ( its ascending) - 525 = 11,550

8 0
2 years ago
The national weather service keeps records of rainfall in valleys. Records indicate that in a certain valley the annual rainfall
Setler79 [48]

Answer:

The mean is 95 and the standard deviation is 2

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Population:

Mean 95, Standard deviation 12

Samples of size 36:

By the Central Limit Theorem,

Mean 95

Standard deviation s = \frac{12}{\sqrt{36}} = 2

4 0
2 years ago
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