Answer:
Given - 3 chairs + 5 tables = 7540 rs
TO find - Price of table
Solution -
Price of chair is Rs 220 ( given)
1 chair = 220
3 chairs = ?
3 × 220
660 Rs
660 rs + 5 tables = 7540 rs
5 tables = 7540 - 660
5 tables = 6880
1 table = 6880/5
= 1376 rs
Price of 5 Table is 6880 and 1 table = 1376 rs
Answer:
Step-by-step explanation:
We have been given a function 
. We are asked to find the zeros of our given function.
To find the zeros of our given function, we will equate our given function by 0 as shown below:
Now, we will factor our equation. We can see that all terms of our equation a common factor that is 
.
Upon factoring out , we will get:
Now, we will split the middle term of our equation into parts, whose sum is 
and whose product is 
. We know such two numbers are 
.
Now, we will use zero product property to find the zeros of our given function.
Therefore, the zeros of our given function are .
Answer:
1. PQ
2. PR
3. OR/OP
4. OR/OP
5. RO
Step-by-step explanation:
4.
-3/4 - 2/3 ÷ (-4/5)
= -3/4 - [2/3 ÷ (-4/5)]
{switch the numerator and denominator when changing from ÷ to ×, or × to ÷}
= -3/4 - [2/3 × (-5/4)]
{numerator × numerator, and denominator × denominator}
= -3/4 - [-10/12]
= -3/4 + 10/12
= -9/12 + 10/12
= 1/12
5.
-2 2/5 + (-2 4/5) × 4/7
= -2 2/5 - (2 4/5 × 4/7)
= -12/5 - (14/5 × 4/7)
= -12/5 - (56/35)
{Simplify fraction to make denominators same}
= -12/5 - (8/5)
= -20/5
= -4/1
= -4
6.
-(-3/5) - 1 3/7 ÷ (-5/14)
{Negative signs cancelled out, fractions compounded}
= 3/5 - 10/7 ÷ (-5/14)
{Switch numerator and denominator when switch from ÷ to ×}
= 3/5 - [10/7 × (-14/5)]
= 3/5 - [-140/35]
= 3/5 + 20/5
= 23/5
{Simplify fraction}
= 4 3/5
Hope this helps! :) You may ask me for more help if you need
Answer:
$8511.11
Step-by-step explanation:
Each year, the amount Walter owes is multiplied by 1.06, so at the end of 6 years, Walter owes 1.06^6 times the amount he borrowed.
he will pay $6,000×1.06^6 ≈ $8511.11
_____
At the end of the first year, Walter owes the original loan amount plus 6% interest. That total is ...
$6000 + 0.06×6000 = $6000×1.06
At the end of the following year, he owes 1.06 times that amount, or ...
6000×1.06²
The amount owed is multiplied by 1.06 each year until Walter pays off the loan.
