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Zina [86]
3 years ago
9

Evaluate 6 + \sqrt(14) + 2 - \sqrt(9) x 2 Answers are in the picture:

Mathematics
1 answer:
Olegator [25]3 years ago
7 0

Hello from MrBillDoesMath!

Answer:

10 - 3 sqrt(2)

Discussion:

Let f(x) =  6 + sqrt(14 + x) - sqrt(9x).  

Then

f(2) =  6 + sqrt(14 + 2) - sqrt(9*2)

      = 6 + sqrt(16) - sqrt(9*2)                 => sqrt(16) = 4

      = 6 + 4 - sqrt(9)*sqrt(2)                   => sqrt(9) = 3

      = 10 - 3 sqrt(2)

which is the first choice.

Thank you,

MrB

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The bar graph below displays students’ responses to the question "What caffeinated drinks do you consume?”
tamaranim1 [39]

Answer:

Yes, because the data are grouped into categories.

Step-by-step explanation:

7 0
3 years ago
Jessica, Chau, and Kareem sent a total of 84 text messages during the weekend. Kareem sent 4 times as many messages as Chau. Jes
swat32

Answer:

Number of messages sent by Chau = 15

Number of messages sent by Kareem = 4 * 15 = 60

Number of messages sent by Jessica = 15 - 6 = 9

Step-by-step explanation:

Let number of messages sent by Chau = c

Number of messages sent by Kareem = 4 times as Chau

                                                                = 4 * c = 4c

Number of messages sent by Jessica = 6 fewer messages than Chau

                                                               = c - 6

Total messages = 84

<u>c + 4c + c</u> - 6 = 84                {Combine like terms}

<u>6c</u> - 6 = 84         {Add 6 to both sides}

6c  = 84 + 6

6c = 90   {Divide both sides by 6}

c = 90/6

c = 15

Number of messages sent by Chau = 15

Number of messages sent by Kareem = 4 * 15 = 60

Number of messages sent by Jessica = 15 - 6 = 9

3 0
3 years ago
Read 2 more answers
The capacity at the local pool is 225 people.
AURORKA [14]

a. 88%

b. 80%

Step-by-step explanation:

198/225=.88

180/225=.80

7 0
3 years ago
Find the probability that when a couple has three ​children, at least one of them is a girl. ​(Assume that boys and girls are eq
Vaselesa [24]
Consider this option (2 ways for this):
1. Probability=1-[probability_all_boys].
for [probability_all_boys]=1/[all_possible_combinations];
for [all_combinations]=2³=8. It means that 
Probability=1-(1/8)=7/8=0.875.
2. Probability=[needed_cases]\[all_possible_cases];
all possible combinations are:
bbb;ggg;bgg;bgb;bbg;gbg;gbb;ggb; - (where 'g' - girl, 'b' - boy) total 8.
needed cases: ggg;bgg;bgb;bbg;gbg;gbb;ggb, - total 7.
Probability=7/8=0.875
7 0
3 years ago
Answer this question please; number 5... show all work thank you
My name is Ann [436]

Answer:

rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour

Step-by-step explanation:

We will make a table of the trip there and back using the formula distance = rate x time

                 d              =            r       x       t

there

back

The distance there and back is 264 miles, so we can split that in half and put each half under d:

               d            =         r        x        t

there    132

back     132

It tells us that the trip there is with the wind and the trip back is against the wind:

           

              d           =        r         x        t

there     132        =    (r + w)

back      132       =     (r - w)

Finally, the trip there took 3 hours and the trip back took 6:

           

             d         =        r        *        t

there    132     =    (r + w)     *       3

back     132     =    (r - w)      *       6

There's the table.  Using the distance formula we have 2 equations that result from that info:

132 = 3(r + w)        and        132 = 6(r - w)

We are looking to solve for both r and w.  We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:

132 = 3r + 3w and

132 - 3w = 3r so

44 - w = r.  Subbing that into the second equation:

132 = 6(44 - w) - 6w and

132 = 264 - 6w - 6w and

-132 = -12w so

w = 11

Subbing w in to solve for r:

132 = 3r + 3(11) and

132 = 3r + 33 so

99 = 3r and

r = 33

7 0
3 years ago
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