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Zina [86]
3 years ago
9

Evaluate 6 + \sqrt(14) + 2 - \sqrt(9) x 2 Answers are in the picture:

Mathematics
1 answer:
Olegator [25]3 years ago
7 0

Hello from MrBillDoesMath!

Answer:

10 - 3 sqrt(2)

Discussion:

Let f(x) =  6 + sqrt(14 + x) - sqrt(9x).  

Then

f(2) =  6 + sqrt(14 + 2) - sqrt(9*2)

      = 6 + sqrt(16) - sqrt(9*2)                 => sqrt(16) = 4

      = 6 + 4 - sqrt(9)*sqrt(2)                   => sqrt(9) = 3

      = 10 - 3 sqrt(2)

which is the first choice.

Thank you,

MrB

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OK my paper says the numerical expression 5+12 represent the sum of 5 and 12. I don't understand
Afina-wow [57]
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represent the sum of 5 and 12, which is the same as 5 + 12 (because the sum is when all the numbers are added up).

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3 years ago
Read 2 more answers
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

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which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

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16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
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and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
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