Can you guys help me find the supplements for question 6

help me on the following, in the picture IK U WANT THE POINTS JUST HELLPPP , ONLY IF UKNOW THE ANSWER/ NO LINKS and swrong answe

earnstyle [38]

Answer:

any coordinate outside the parabola is a reasonable answer.

Step-by-step explanation:

test the solution (0, 0) and if if that number is greater than 0 then the rest of the points outside on the inside are.

x = 0

y = 0

(0)^2 - 2(0) - 3 = -3

-3 is less than 0 so (0, 0) is not a possibility so any coordinate outside the parabola is a reasonable answer.

3 0

3 years ago

Cristina uses a ruler to measure the length of her math textbook.she says that the book is 4/10 meter long.Ise her measurement i

NNADVOKAT [17]

The simplest form iz 2/5

3 0

3 years ago

Could somebody pls help me with this question

natulia [17]

simplify to 1 hour which will be 6 minutes in 1 hour

in 3 hours it will be 18 minutes

5 0

3 years ago

Read 2 more answers

If you roll two number cubes ,what is the probability of their sum being 9 or higher?

bija089 [108]

Answer:

5/18

Step-by-step explanation:

When two cubes are rolled there are 36 possibilities

Each dice has 6 equally like outcomes so possibilities are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we look at the pair that has sum equal to 9

(3,6) (4,5) (5,4) (6,3) that has sum of 9

Probability of sum is 9 = $\frac{4}{36}$

we look at the pairs that has sum greater than 9

(4,6) (5,5)(5,6) (6,4)(6,5)(6,6)

Probability of sum greater than 9 = $\frac{6}{36}$

Probability of sum 9 or higher = P(sum 9) + P(greater than 9)

= $\frac{4}{36}+\frac{6}{36}= \frac{10}{36}=\frac{5}{18}$

4 0

3 years ago

Suppose that the amount of time T a customer spends in a bank is exponentially distributed with an average of 10 minutes. What i

Bad White [126]

Answer:

The probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes is 0.6065.

Step-by-step explanation:

The random variable T is defined as the amount of time a customer spends in a bank.

The random variable T is exponentially distributed.

The probability density function of a an exponential random variable is:

$f(x)=\lambda e^{-\lambda x};\ x>0$

The average time a customer spends in a bank is β = 10 minutes.

Then the parameter of the distribution is:

$\lambda=\frac{1}{\beta}=\frac{1}{10}=0.10$

An exponential distribution has a memory-less property, i.e the future probabilities are not affected by any past data.

That is, P (X > s + x | X > s) = P (X > x)

So the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes is:

P (X > 15 | X > 10) = P (X > 5)

$\int\limits^{\infty}_{5} {f(x)} \, dx =\int\limits^{\infty}_{5} {\lambda e^{-\lambda x}} \, dx\\=\int\limits^{\infty}_{5} {0.10 e^{-0.10 x}} \, dx\\=0.10\int\limits^{\infty}_{5} {e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10}|^{\infty}_{5}\\=[-e^{-0.10 \times \infty}+e^{-0.10 \times 5}]\\=0.6065$

Thus, the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes is 0.6065.

8 0

3 years ago