Answer:
multiply 31.4x7.9 then add 9.5 to the answer to multiplication prob. Then add your answer in the first sentence. Then multiply 4.6 x 2 . I think that right,good luck : ) luck.
The answer is 3.75 or 3 3/4
Answer:
0 <=t<=21
Step-by-step explanation:
Projectile is Moving upwards on an interval of (0 to 21), if we plot Velocity vs Time and denote positive y-axis above 0 and negative y-axis below 0(for velocity), then from 0 to 21 t projectile is moving upwards and has positive velocity, when the projectile reaches the top of it's motion and returns back down to ground it's velocity is negative and is plotted below the y =0 (note that is for t > 21).
hence for the interval 0 <=t <=21 the instantaneous velocity is positive (Note, instantaneous velocity is also the derivative of the velocity or the slope ).
Answer:
8t(t - 5)^2
Step-by-step explanation:
I would immediately rearrange these terms in descending order by powers of t:
8t^3 - 80t^2 + 200t
Then I'd factor out 8t:
8t(t^2 - 10 t + 25).
Finally, I'd factor the quadratic t^2 - 10 t + 25:
(t - 5)^2
and so 200t+8t^3-80t^2 in factored form is 8t(t - 5)^2.
Answer:
i can help if you zoom in and repost it
Step-by-step explanation:
