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Gwar [14]
2 years ago
5

The population of a town increased by 10% per year in 2009, 2010, and 2011. If the population of the town at the beginning of 20

09 was 40,000, what was it at the end of 2011?
Mathematics
1 answer:
natta225 [31]2 years ago
3 0
So, 10% of 40,000 is 4,000 then we add up 40,000 and 4,000 and get 44,000. Then we need to know how much is 10% of 44,000 and it is 4,400. 44,000+4,400= 48,400 and then we just need to repeat this one more time. 48,400+4,840(10% of 48,400)= 53,240. That is the answer))))
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3 years ago
Evaluate the given integral by changing to polar coordinates. 8xy dA D , where D is the disk with center the origin and radius 9
BabaBlast [244]

Answer:

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Step-by-step explanation:

∫∫8xydA

converting to polar coordinates, x = rcosθ and y = rsinθ and dA = rdrdθ.

So,

∫∫8xydA = ∫∫8(rcosθ)(rsinθ)rdrdθ = ∫∫8r²(cosθsinθ)rdrdθ = ∫∫8r³(cosθsinθ)drdθ

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∫∫8r³(cosθsinθ)drdθ = 8∫[∫r³dr](cosθsinθ)dθ

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= 8[6561/4]∫(cosθsinθ)dθ

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Since sin2θ = 2sinθcosθ, sinθcosθ = (sin2θ)/2

Substituting this we have

13122∫(cosθsinθ)dθ = 13122∫(1/2)(sin2θ)dθ

= 13122/2[-cos2θ]/2 from 0 to 2π

13122/2[-cos2θ]/2 = 13122/4[-cos2(2π) - cos2(0)]

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= -13122/4[1 - 1]

= -13122/4 × 0

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2 years ago
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Schach [20]

Answer:

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So pie is 3.14

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This is equal to 502.4

Hope it helped

5 0
2 years ago
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