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Gwar [14]
2 years ago
5

The population of a town increased by 10% per year in 2009, 2010, and 2011. If the population of the town at the beginning of 20

09 was 40,000, what was it at the end of 2011?
Mathematics
1 answer:
natta225 [31]2 years ago
3 0
So, 10% of 40,000 is 4,000 then we add up 40,000 and 4,000 and get 44,000. Then we need to know how much is 10% of 44,000 and it is 4,400. 44,000+4,400= 48,400 and then we just need to repeat this one more time. 48,400+4,840(10% of 48,400)= 53,240. That is the answer))))
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Answer:

The  value is  P( H \  n \  T ) =  0.6049

Step-by-step explanation:

From the question we are told that

   The  number of times  is  n  =  20  

   The probability of getting three or more heads in a row is  P(H) =  0.7870

   The probability of getting three or more heads in a row or three or more tails in a row is    P(H \ u \   T )  =  0.9791

Generally given that it is a fair coin , then   P(H) = P(T) =  0.7870

Here  P(T) is  probability of getting three or more tails  in a row

Generally  the probability of getting three or more heads in a row and three or more tails in a row is mathematically represented as

        P( H \  n \  T ) =  P(H) + P(T) -  P( H \  u \  T )

=>   P( H \  n \  T ) =  0.7870  + 0.7870 -  0.9791

=>   P( H \  n \  T ) =  0.6049

 

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2 years ago
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