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3 years ago

Prove ABC~EDC ?

Mathematics

1 answer:

erastova [34]3 years ago

8 0

Answer:

AA similarity theorem

Step-by-step explanation:

we know that

<u>AA (Angle-Angle) Similarity</u> states that In two triangles, if two pairs of corresponding angles are congruent, then the triangles are similar

In this problem we have that

∠BCA=∠ECD ----> by vertical angles

∠BAC=∠DEC ---> because AB is parallel to ED (alternate interior angles)

therefore

Triangles ABC and EDC are similar by AA similarity theorem

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