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Ainat [17]
3 years ago
10

If m(-12) =0 is the result of M(x) using the reminder theorem then what do -12 and 0 represent?

Mathematics
1 answer:
lions [1.4K]3 years ago
3 0

Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that

Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as

Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.

Now consider two polynomials of degree 2. In this case we seek a single value of x such that

Hope this helped, Hope I did not make it to complated

Please give me Brainliest

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What 17 multiply and adds to get -2
Marrrta [24]
17 * 0 + -2.

Now we rewrite the equation and make it 17 * 0 - 2 and u get -2.
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Pls help for this question! no wrong answers pls
ankoles [38]

Answer:

41.29 cm²

Step-by-step explanation:

From the question,

Area of the shaded portion = Area of the circle - area of the square.

A' = πr²-L²...… Equation 1

Where A' = Area of the shade portion, r = radius of the circle, L = length of the square, π = pie

Given: r = 4 cm, L = 3 cm

Constant: π = 22/7.

Substitute these values into equation 1

A' = [(22/7)×4²]-3²

A' = 50.29-9

A' = 41.29 cm²

Hence the area of the shaded portion is 41.29 cm²

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3 years ago
a coin is tossed and a number cube is rolled what is the probability that the coin shows heads and the number cube shows 5
Reptile [31]

Answer:

If it is a 6 sided dice, then the probability will be roughly a 1 in 12 chance

Step-by-step explanation:

I think, not entirely sure, sorry if it is wrong

8 0
3 years ago
In 2000 the total amount of gamma ray bursts was recorded at 6.4 million for a city. In 2005, the same survey was made and the t
ratelena [41]

Let's assume

It started in 2000

so, t=0 in 2000

P_0=6.4million

we can use formula

P(t)=P_0 e^{rt}

we can plug value

P(t)=6.4 e^{rt}

In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million

so, at t=2005-2000=5

P(t)=7.3 million

we can plug value and then we can solve for r

7.3=6.4 e^{r*5}

r=0.02632

now, we can plug back

P(t)=6.4 e^{0.02632t}

now, we have

P(t)=1 billion =1000 million

so, we can set it and then we can solve for t

1000=6.4 e^{0.02632t}

t=191.924

approximately

t=192

Year is 2000+192

year is 2192................Answer

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The x-intercept of 5y+2x20 is (10.0) True False
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Answer:

answer

the answer is false

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