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Answer:
Therefore we can say that 98 boxes will be needed to hold all the paperweights.
Step-by-step explanation:
i) there are 1657 souvenir paperweights that need to be packed in boxes.
ii) each box will hold 17 paperweights
iii) therefore the number of boxes that will be needed are
= =
= 97.471
iv) Therefore we can say that 98 boxes will be needed to hold all the paperweights.
Let's rewrite the binomial as:
Using the binomial expansion, we get:
For the 15th term, we want the term where r is equal to 14, because of the fact that the first term starts when r = 0. Thus, for the 15th term, we need to include the 0th or the first term of the binomial expansion.
Thus, the fifteenth term is:
Using the binomial expansion, we get:
For the 15th term, we want the term where r is equal to 14, because of the fact that the first term starts when r = 0. Thus, for the 15th term, we need to include the 0th or the first term of the binomial expansion.
Thus, the fifteenth term is: