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BartSMP [9]
4 years ago
6

-1.1 devide by -2 need help with this

Mathematics
2 answers:
Allushta [10]4 years ago
6 0

Answer:

11/20 or 0.55

Step-by-step explanation:

-1.1÷-2=0.55

Oksi-84 [34.3K]4 years ago
3 0

Answer:

Step-by-step explanation:

-1.1 divided by -2 would be -3

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A rectangular parking lot has an area of 315 square yards. The width of the parking lot is 5 yards longer than the length of the
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Answer:

Dimension of parking lot is approximately 15.425 × 20.425 yards.

Step-by-step explanation:

Given:

Area of the parking lot = 315 \ yd^2

Let the length of the parking lot be 'l'

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The width of the parking lot is 5 yards longer than the length of the parking lot.

so we can say that;

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Solution:

Now we can say that;

Area of rectangle is equal to length times width.

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Now substituting the value of w in above equation we get;

l(l+5)=315\\\\l^2+5l=315\\\\l^2+5l-315=0

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ax^2+bx+c =0

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c=-315

Formula for quadratic equation is;

l =\frac{-b\±\sqrt{b^2-4ac}}{2a}

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\sqrt{b^2-4ac} = \sqrt{5^2-4\times1\times-315} =\sqrt{25+1260}=\sqrt{1285}  \approx35.85

Now we will substitute the value we get;

l =\frac{-5\±35.85}{2\times1}= \frac{-5\±35.85}{2}

Now we will find 2 roots we get;

l= \frac{-5+35.85}{2}= \frac{30.85}{2}\approx15.425\\\\OR\\\\l =\frac{-5-35.85}{2}= \frac{-40.85}{2} \approx -20.425

Now we get 2 values of length one is positive and other is negative.

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Hence the length of the parking lot = 15.425 yards

Width of the rectangular parking lot = l+5=15.425+5 =20.425

Hence we can say that dimension of parking lot is approximately 15.425 × 20.425 yards.

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