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Yakvenalex [24]
3 years ago
14

2 ( 4x - 3 ) - 8 = 4 + 2x Giving me a headache

Mathematics
2 answers:
Advocard [28]3 years ago
4 0

1 Expand.

8x-6-8=4+2x8x−6−8=4+2x

2 Simplify  8x-6-88x−6−8  to  8x-148x−14.

8x-14=4+2x8x−14=4+2x

3 Add 1414 to both sides.

8x=4+2x+148x=4+2x+14

4 Simplify  4+2x+144+2x+14  to  2x+182x+18.

8x=2x+188x=2x+18

5 Subtract 2x2x from both sides.

8x-2x=188x−2x=18

6 Simplify  8x-2x8x−2x  to  6x6x.

6x=186x=18

7 Divide both sides by 66.

x=\frac{18}{6}x=

​6

​

​18

​​

8 Simplify  \frac{18}{6}

​6

​

​18

​​   to  33.

x=3x=3

Done Hope this helps let me know if u have any questions thank you

Karo-lina-s [1.5K]3 years ago
3 0

Answer:

Step-by-step explanation:

1 Expand.

8x-6-8=4+2x8x−6−8=4+2x

2 Simplify  8x-6-88x−6−8  to  8x-148x−14.

8x-14=4+2x8x−14=4+2x

3 Add 1414 to both sides.

8x=4+2x+148x=4+2x+14

4 Simplify  4+2x+144+2x+14  to  2x+182x+18.

8x=2x+188x=2x+18

5 Subtract 2x2x from both sides.

8x-2x=188x−2x=18

6 Simplify  8x-2x8x−2x  to  6x6x.

6x=186x=18

7 Divide both sides by 6.

x= ​18/6

​​  

8 Simplify  18/6 to 3

x=3

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hram777 [196]

Answer:

\frac{63}{15  - c} - \frac{63}{15  + c} = 4

Step-by-step explanation:

The systems of equations are

Let us assume the rate of the current be c

Now actual speed against the current is (15 - c)

And, the actual speed with the current is (15 + c)

Here we applied the time formula i.e. distance by speed

Also the upstream time  - downstream time = 4

Now the equations are

\frac{63}{15  - c} - \frac{63}{15  + c} = 4

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Step-by-step explanation:

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Solve the equation by factoring: x^2 - 5x = 14
daser333 [38]

Answer:

x=7,  x=  -2

Step-by-step explanation:

  1. Start by putting the whole equation to one side:  x2-5x=14 ---->               x2-5x-14=0
  2. Next, factor the equation:  x,x    -7,2 ----> (x-7)(x+2)=0
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Simplify completely x^2+4x-5/5x^2-8x+3
arlik [135]

Answer:

\boxed{\bold{\frac{x+5}{5x-3}}}

Explanation:

[ Step One ] Factor \bold{x^2+4x-5}

\bold{x\left(x-1\right)+5\left(x-1\right)}

[ Step Two ] Rewrite Equation

\bold{\frac{\left(x-1\right)\left(x+5\right)}{5x^2-8x+3}}

[ Step Three ] Factor \bold{5x^2-8x+3}

\bold{\left(x-1\right)\left(x+5\right)}

[ Step Four ] Rewrite Equation

\bold{\frac{\left(x-1\right)\left(x+5\right)}{\left(5x-3\right)\left(x-1\right)}}

[ Step Five ] Cancel Out Common Factor \bold{x-1}

\bold{\frac{x+5}{5x-3}}

\boxed{\bold{Mordancy}}

5 0
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