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adoni [48]
3 years ago
7

Lim ln(tan x) as tends to pi/2 from the left

Mathematics
1 answer:
ioda3 years ago
3 0
Let x=\arctan y. Then \tan x=y, and so as x\to\dfrac\pi2^-, you have y\to+\infty. The limit is then equivalent to

\displaystyle\lim_{x\to\frac\pi2^-}\ln(\tan x)=\lim_{y\to\infty}\ln y=\infty
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