If it takes Jake 5 minutes to do 1 3rd of a mile how much miles would he do in a hour

Mathematics

1 answer:

BaLLatris [955]3 years ago

7 0

Answer:

Step-by-step explanation:

it takes 15 mins to do 1 mile (3 times 5) and 60 mins divided by 15 would be 4 . so 4 miles

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A classic counting problem is to determine the number of different ways that the letters of “dissipate” can be arranged. Find th

alexdok [17]

Answer:

90720 ways

Step-by-step explanation:

Since there are 9 letters, there are 9! ways to arrange them. However since there are repeating letters, we have to divide to remove the duplicates accordingly. There are 2 ‘s’ and 2 ‘i’ hence:

Number of way to arrange ‘dissipate’ = 9! / (2! x 2!) = 90720 ways

Hence there are 90720 ways to have the number of dissipate in the letter.

6 0

3 years ago

A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A

julsineya [31]

Answer:

a) -13.9 ft/s

b) 13.9 ft/s

Step-by-step explanation:

a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:

$D^{2} = (90 - x)^{2} + 90^{2}$ (1)

$\frac{d(D^{2})}{dt} = \frac{d(90 - x)^{2} + 90^{2})}{dt}$

$2D\frac{d(D)}{dt} = \frac{d((90 - x)^{2})}{dt}$

$D\frac{d(D)}{dt} = -(90 - x) \frac{dx}{dt}$ (2)

Since:

$D = \sqrt{(90 -x)^{2} + 90^{2}}$

When x = 45 (the batter is halfway to first base), D is:

$D = \sqrt{(90 - 45)^{2} + 90^{2}} = 100. 62$

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

$100.62 \frac{d(D)}{dt} = -(90 - 45)*31$

$\frac{d(D)}{dt} = -\frac{(90 - 45)*31}{100.62} = -13.9 ft/s$

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.

b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

$D^{2} = 90^{2} + x^{2}$