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2 years ago

F(x) = x^2 is stretched vertically by a factor of 4 and shifted 1 unit down. equation = ???

Mathematics

1 answer:

LenKa [72]2 years ago

6 0

Answer:

f(x) = 4x² - 1

Step-by-step explanation:

The given function is; f(x) = x²

Now, when stretched vertically by a factor of 4, we have;

f(x) = 4x²

It's now shifted 1 unit down.. Thus, the final function will be;

f(x) = 4x² - 1

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A theater has 60 seats in the first row, 68 seats in the second row, 76 seats in the third row, and so on in the same increasing

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Step-by-step explanation:a1=60

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3 years ago

Mark is going to an awards dinner and wants to dress appropriately. He has one blue dress shirt, one white dress shirt, one blac

dlinn [17]

Solution:

Outfit Shirt Slacks Tie

Outfit 1 Blue Black Red

Outfit 2 Blue Grey Red

Outfit 3 White Black Red

Outfit 4 White Grey Red

Outfit 5 Black Black Red

Outfit 6 Black Grey Red

We take the outfits 1, 2 , 5 and 6 as a subset of the sample space.

So these 1, 2, 5 and 6 consists either a blue shirt or a black shirt.

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2 years ago

What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10

jasenka [17]

<u>Answer:</u>

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

<u>Solution: </u>

The given expression is $(2 x-3 y)^{10}$

As per binomial theorem, we know,

$(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}$

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now $x^{5}\times y^5$ will be the 6 term where k =5

Now, $\mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}$

So, the coefficient of $x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right$ .

$10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252$

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

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3 years ago

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yuradex [85]

Answer:

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