Answer:
def prompt_number():
while True:
number = int(input("Enter a number: "))
if number >= 0:
break
return number
def compute_sum(n1, n2, n3):
total = n1 + n2 + n3
return total
n1 = prompt_number()
n2 = prompt_number()
n3 = prompt_number()
result = compute_sum(n1, n2, n3)
print(result)
Explanation:
Create a function named prompt_number that asks the user to enter a number until a positive number or 0 is entered and returns the number
Create a function named compute_sum that takes three numbers, sums them and returns the sum
Ask the user to enter three numbers, call the prompt_number() three times and assign the values
Calculate the the sum, call the compute_sum and pass the numbers as parameters
Print the result
Doubly linked chain
When a linked chain contains nodes that reference both the next node and the previous node, it is called a doubly linked chain. This type of chain is often used in data structures because it provides a way to easily traverse the data in both directions. However, because each node must reference both the next node and the previous node, doubly linked chains require more memory than singly linked chains.
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