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zimovet [89]
3 years ago
8

What OS has a large market share but is limited because it can be installed only on one particular brand?

Computers and Technology
2 answers:
Evgesh-ka [11]3 years ago
4 0
Answer your looking for is Mac OS
lakkis [162]3 years ago
3 0

Answer:

Mac OS

Explanation:

Mac OS can only be installed by the distributer of the computer. The company who makes these computers is called Apple.

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Acrynom for wys or wyg
REY [17]
What you said? And what you get?
8 0
3 years ago
Write a program that reads numbers from scanf (keyboard) and then sums them, stopping when 0 has been entered. Construct three v
almond37 [142]

Answer:

For loop Version:

#include <stdio.h>

int main()

{

   int number, sum = 0;

   printf("Enter a positive integer: ");

   scanf("%d", &number);

   

   for (int i = 0; i <= number; i++) {

       if(number == 0)

           break;

       sum += number;

       

       printf("Enter a positive integer: ");

       scanf("%d", &number);

   }

   printf("Sum is: %d", sum);

   return 0;

}

- - - - -

While Loop Version:

#include <stdio.h>

int main()

{

   int number, sum = 0, i = 0;

   printf("Enter a positive integer: ");

   scanf("%d", &number);

   

   while (number != 0) {

       sum += number;

       

       printf("Enter a positive integer: ");

       scanf("%d", &number);

   }

   printf("Sum is: %d", sum);

   return 0;

}

Do-while Loop Version:

#include <stdio.h>

int main()

{

   int number, sum = 0, i = 0;

   

   do {

       printf("Enter a positive integer: ");

       scanf("%d", &number);

       

       sum += number;

       

   } while (number != 0);

   printf("Sum is: %d", sum);

   return 0;

}

Explanation:

- Initialize the variables

- Ask the user for the numbers until the user enters 0

-  Calculate and print the sum

4 0
3 years ago
Write a loop that displays all possible combinations of two letters where the letters are 'a', or 'b', or 'c', or 'd', or 'e'. T
nikitadnepr [17]

Answer:

The program to this question can be given as:

Program:

#include <stdio.h> //include header file.

int main() //defining main method

{

char i,j; //defining variable

for  (i='a'; i<='e'; i++) //outer loop for column

{

for (j='a'; j<='e'; j++) //inner loop for row

{

printf("%c%c\n",i,j); //print value

}

}

return 0;

}

Output:

image.

Explanation:

  • In the above C language program, firstly a header file is included. Then the main method is defined in this, a method contains a char variable that is "i and j". This variable is used in for loop, that is used to print the pattern.
  • To print the following patter two for loop is used the outer loop is used for print columns and the inner loop prints row.
  • In C language to print character, we use "%c" inside a loop print function is used, that prints characters.

3 0
3 years ago
Universal Containers has a requirement to integrate Salesforce with an external system to control record access. What option sho
Inessa05 [86]

Answer:

C. Use the SOAP API to maintain the related SObject_share records

8 0
3 years ago
Consider the following Stack operations:
maxonik [38]

Answer:

Sequence of popped values: h,s,f.

State of stack (from top to bottom): m, d

Explanation:

Assuming that stack is  initially empty. Suppose that p contains the popped values. The state of the stack is where the top and bottom are pointing to in the stack. The top of the stack is that end of the stack where the new value is entered and existing values is removed. The sequence works as following:

push(d) -> enters d to the Stack

Stack:  

d ->top

push(h) -> enters h to the Stack

Stack:

h ->top

d ->bottom

pop() -> removes h from the Stack:

Stack:

d ->top

p: Suppose p contains popped values so first popped value entered to p is h

p = h

push(f) -> enters f to the Stack

Stack:

f ->top

d ->bottom

push(s) -> enters s to the Stack

Stack:

s ->top

f

d ->bottom

pop() -> removes s from the Stack:

Stack:

f ->top

d -> bottom

p = h, s

pop() -> removes f from the Stack:

Stack:

d ->top

p = h, s, f

push(m) -> enters m to the Stack:

Stack:

m ->top

d ->bottom

So looking at p the sequence of popped values is:

h, s, f

the final state of the stack:

m, d

end that is the top of the stack:

m

6 0
3 years ago
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