Answer:
52°
Step-by-step explanation:
(I'm assuming lines JK and HI are parallel)
∠JKA and ∠HIA are corresponding so they are congruent.
Therefore, since ∠JKA is 62, so is ∠HIA. Then knowing the sum of interior angles of a triangle always must be 180, you can just do the math to get 52° as the remaining angle.
66° + 62° + ∠x = 180
∠x = 52°
Answer:
I'm think is 17
Step-by-step explanation:the Height of it was 18 and the original height was 2 so subtract 2 from 18 you get 16.So thy are adding 16.So 16+1=17.
Let: eq 1:2x+5y=-55
eq 2:y=3x+6
by substituting eq 2 in eq 1 we get,
2x+5(3x+6)=-55
2x+15x+30+55=0
17x + 85=0
x=-85/17
x=-5
By substituting x value in eq 2,
we have,
y=3(-5)+6=-15+6=-9
Hey there, Dudedan!
In a#b = a+2b, we have the first term, a, plus 2 times the second term, b.
Let's try that with 3#4.
3#4 = 3+2(4) =
3 + 8 = 11.
Hope this helps!
(2,-5),(-1,4)
slope = (4 - (-5) / (-1 - 2) = (4 + 5) / -3 = -9/3 = -3 <==
