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Serggg [28]
3 years ago
6

Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.)

an = 7n 1 + 8n lim n→[infinity] an = Incorrect:
Mathematics
1 answer:
Hoochie [10]3 years ago
3 0

Answer:

The sequence diverges

Step-by-step explanation:

Given the sequence:

a_n=7n(1+8n)=7n+56n^2

Let's use the zero test which states:

\Sigma a_n\\Diverges\hspace{3}if\hspace{3} \lim_{n \to \infty} a_n \neq0

So, let's find the limit:

\lim_{n \to \infty} 7n+56n^2= \lim_{n \to \infty} 7n + \lim_{n \to \infty} 56n^2

For the first limit:

\lim_{n \to \infty} 7n= 7  \lim_{n \to \infty} n=7* \infty=\infty

For the second limit:

\lim_{n \to \infty} 56n^2=56 \lim_{n \to \infty} n^2 =56(\infty)^2=\infty

So:

\lim_{n \to \infty} 7n+56n^2=\infty +\infty=\infty

Therefore, the sequence diverges

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