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belka [17]
3 years ago
13

part b is: if the energy release of one earthquake is 10,000 times that of another, how much larger is the Richter scale reading

of the larger earth quake than the smaller? will give brainliest!!!!

Mathematics
2 answers:
kotegsom [21]3 years ago
8 0

You could use the information from part A to get B. I'm not sure if you want A or not, so I'll do it as well.

A

Eo = 10^4.4 Joules

E = 2 * 10^15

Formula

M = (2/3) log (E/Eo)

M = 2/3 * log (2 * 10^15/10^(4.4) )

M = 2/3 * log( 7.9621* 10^10)

M = 2/3 * 10.901

M = 7.26735 on the Richter scale. That is a huge amount of energy.

Part B

Suppose that you use Eo and your base. Eo is 10^4.4

Now the new earthquake is E = 10000 * Eo

So what you get now is M = (2/3)* Log(10000 * Eo / Eo )

The Eo's cancel out.

M = 2/3 * log(10000)

M = 2/3 of 4

M = 8/3

M = 2.6667 difference in the Richter Scale Reading. It is still an awful lot of energy.

What this tells you is that if the original reading was (say) 6 then the 10000 times bigger reading would 8.266667

Answer: M = 2.6667


pychu [463]3 years ago
8 0

Answer:

he is right i think

Step-by-step explanation:

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Data given and notation

\bar X=3.4 represent the sample mean  

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n=50 sample size  

\mu_o =3.3 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

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p_v represent the p value for the test (variable of interest)  

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We can replace in formula (1) the info given like this:  

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