Solve for c. 3 − 7c − 20c = 7(–7c − 19) + 14c c =

Mathematics

2 answers:

Studentka2010 [4]3 years ago

8 0

Answer:

c = -17

Step-by-step explanation:

→Distribute the 7 to (-7c - 19):

3 - 7c - 20c = -49c - 133 + 14c

→Add like terms (-7c and -20c, -49c and 14c):

3 - 27c = -35c - 133

→Add 35c to both sides:

3 + 8c = -133

→Subtract 3 from both sides:

8c = -136

→Divide both sides by 8:

c = -17

OleMash [197]3 years ago

7 0

Answer:

$\boxed{c = -17}$

Step-by-step explanation:

$= > 3 - 7c - 20c = 7( - 7c - 19) + 14c \\ \\ = > 3 - 27c = ( - 7c \times 7) - (7 \times 19) + 14c \\ \\ = > 3 - 27c = - 49c - 133 + 14c \\ \\ = > 3 - 27c = - 35c - 133 \\ \\ = > 3 - 27c + 35c = - 133 \\ \\ = > 3 + 8c = - 133 \\ \\ = > 8c = - 133 - 3 \\ \\ = > 8c = - 136 \\ \\ = > c = - \frac{136}{8} \\ \\ = > c = - 17$

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Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with

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Answer:

$z$

Step-by-step explanation:

Assuming this complete question:

"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean $\mu =26$ kilograms and standard deviation $\sigma=4.2$ kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.

$X$ "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(26,4.2)$