Answer:
(i) (f - g)(x) = x² + 2·x + 1
(ii) (f + g)(x) = x² + 4·x + 3
(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2
Step-by-step explanation:
The given functions are;
f(x) = x² + 3·x + 2
g(x) = x + 1
(i) (f - g)(x) = f(x) - g(x)
∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1
(f - g)(x) = x² + 2·x + 1
(ii) (f + g)(x) = f(x) + g(x)
∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3
(f + g)(x) = x² + 4·x + 3
(iii) (f·g)(x) = f(x) × g(x)
∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2
(f·g)(x) = x³ + 4·x² + 5·x + 2
Answer:
your answer is C) A negative radius does not make sense.
Step-by-step explanation:
hope it helps ^_^
Answer:
or 
(they're the same)
Step-by-step explanation:
- Simplify:
- Find a common denominator. The LCM of 6 and 5 is 30, so multiply the numerator and the denominator by the same thing: 6 × 5 = 30, -9 × 5 = -45, 5 × 6 = 30, 3 × 6 = 18
- Write the new fractions:
- Subtract: -45/30 - 18/30 =
I hope this helps!
Answer:
You didnt show the table, not sure how to answer
Step-by-step explanation:
