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mr_godi [17]
2 years ago
12

What is the area of a circle with a Radius of 4 and a Diameter of 2? (Its on Khan)

Mathematics
1 answer:
algol132 years ago
7 0

Answer:4^2≈50.26548

Step-by-step explanation:

   πr2.

   Where r is the radius and π≈3.14 , the ratio of a circle's circumference to    its diameter.

   Plugging in 4 from the radius, we get.

   42π

   ⇒16π inches.

   This is our exact answer. Alternatively, we can plug in 3.14 for π to get.

   50.26 inches.

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No linksWhich value completes the equation?
sergeinik [125]

Answer:

800

Step-by-step explanation:

divide 5 and 8

4 0
2 years ago
Carl wants to plant a garden that is 1 1/2 yards long and has an area of 3 1/2 yd.² how wide should the Garden be
lesya692 [45]
L= length= 1 1/2 yards
A= area= 3 1/2 yards^2
w= width

Area= length * width
plug in numbers you know
3 1/2= (1 1/2)(w)
convert to improper fractions
(3*2+1)/2= ((1*2+1)/2)(w)
7/2= 3/2w
divide both sides by 3/2
7/2 ÷ 3/2= w
to divide fractions, multiply by the reciprocal/inverse of 3/2
7/2 * 2/3= w
(7*2)/(2*3)= w
14/6= w
reduce by 2
7/3= width as improper fraction
OR
2 1/3= width as mixed fraction

ANSWER: The width should be 2 1/3 yards wide (or 7/3 yards wide).

Hope this helps! :)
8 0
3 years ago
Use the distributive property to match equivalent expressions.
vekshin1

Answer: 7(-4-x) —> -28-7x. 7(4+x) —> 28+7x. -7(-4+x) —> 28-7x. -7(4-x) —> -28+7x

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Below are two parallel lines with a third line intersecting them
olga_2 [115]

Answer:

x = 122

Step-by-step explanation:

x = 122 because of alternate interior angles

3 0
3 years ago
Read 2 more answers
Find the area of an octagon whose perimeter is 120 cm.
stira [4]

Answer:

The area of an octagon whose perimeter is 120 cm is 1086.4 cm^{2}

Step-by-step explanation:

An octagon is a polygon with eight sides. If the lengths of all the sides and the measurement of all the angles are equal, the octagon is called a regular octagon.

There is a predefined set of formulas for the calculation of perimeter, and area of a regular octagon.

The perimeter of an Octagon is given by

P=8a

and the area of an Octagon is given by

A=2a^{2}(1+\sqrt{2})

We know that the perimeter is 120 cm, solving for side length (a) in the perimeter formula we get

120=8a\\\frac{8a}{8}=\frac{120}{8}\\a=15

Now, we calculate the area

A=2a^{2}(1+\sqrt{2})\\A=2(15)^{2}(1+\sqrt{2})\\A=450\left(1+\sqrt{2}\right)\\A\approx 1086.4 \:cm^{2}

5 0
3 years ago
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