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3 years ago

The choices are:

Mathematics

1 answer:

Harrizon [31]3 years ago

7 0

Let's take a look at D:

D) y = (x-1)^2 - 16 Compare this to
y = (x-h)^2 + k This is the std. equation of a parabola in vertex form.

You can see, by comparison, that h=1 and k= -16; these are the coordinates of the vertex, clearly shown in the diagram.

Since the coefficient of (x-h)^2 is +1, the graph opens upward (which the given graph confirms), and is neither compressed nor stretched vertically.

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Confused from where I left off PLEASE help

Leviafan [203]

Not sure the right equation so i did both....

#1 - √12m√15m=1m√2

Simplifies to:

13.416408m2=1.414214m

Let's solve your equation step-by-step.

13.416408m2=1.414214m

Step 1: Subtract 1.414214m from both sides.

13.416408m2−1.414214m=1.414214m−1.414214m

13.416408m2−1.414214m=0

Step 2: Factor left side of equation.

m(13.416408m−1.414214)=0

Step 3: Set factors equal to 0.

m=0 or 13.416408m−1.414214=0

m=0 or m=0.105409

Answer: m=0 or m=0.105409

#2 - √12m√15m

Simplifies to:

13.416408m2

=13.416408*m2

=13.416408*(m*m)

=13.416408m2

Can I get a brainliest Please & Thank you...

4 0

3 years ago

Read 2 more answers

The box and whiskers plot represents the results of the same math test being given to two different classes. According to the bo

densk [106]

Answer: Answer A: Both classes have a range of 45

Step-by-step explanation:

above the two graphs we can see a number line ranging from 50-100

bellow that, we can see 2 box and whisker plots, one for second period and one for fourth period. the larger rectangular boxes show all the number results, the line in between them states the average result. Both lines have starting points at 55 and ending points at 100.

100-55=45 45 being the range. Since 2nd and 4th both share the same range answer A could possibly be correct

B is wrong because 2nd period has a median of 90

C is wrong because no periods have a median of 100

D is wrong because most of the students scored an 85+

conclusion: answer A is correct

4 0

3 years ago

Read 2 more answers

A pack of folders has a length of 5 inches, a width of 12 inches, and a height of 1 inch. The pack of folders will be shipped in

777dan777 [17]

Answer:

A) Each pack of folders has a volume of 60 cubic inches.

B) The box has a volume of about 720 cubic inches

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

Step-by-step explanation:

Verify each statement

A) Each pack of folders has a volume of 60 cubic inches.

The statement is True

Because

The volume of each pack of folders is equal to

$V=(5)(12)(1)=60\ in^{3}$

B) The box has a volume of about 720 cubic inches

The statement is True

Because

The volume of the box is equal to the volume of one pack of folders multiplied by 12

$V=(12)60=720\ in^{3}$

C) If the box held 15 packs of folders, it would have a volume of about 1,200 cubic inches

The statement is False

Because

Applying proportion

$\frac{12}{720}\frac{packs}{in^{3}}=\frac{15}{x}\frac{packs}{in^{3}}\\ \\x=720*15/12\\ \\x=900\ in^{3}$

$900\ in^{3}\neq 1,200\ in^{3}$

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

The statement is True

Because

Applying proportion

$\frac{12}{720}\frac{packs}{in^{3}}=\frac{20}{x}\frac{packs}{in^{3}}\\ \\x=720*20/12\\ \\x=1,200\ in^{3}$

$1,200\ in^{3}= 1,200\ in^{3}$

E) Each pack of folders has a volume of 24 cubic inches.

The statement is False

Because

The volume of each pack of folders is equal to

$V=(5)(12)(1)=60\ in^{3}$

7 0

3 years ago

11 The net force on a vehicle that is accelerating at a rate of 1.5 m/s² is 2,800 newtons. What is

ololo11 [35]

Answer:

$Mass = 1867kg$

Step-by-step explanation:

Given

$Force = 2800N$

$Acceleration = 1.5m/s^2$

Required

Determine the mass of the vehicle

This question will be answered using Newton's second law

$Force = Mass * Acceleration$

Substitute values for Force and Acceleration

$2800 = Mass * 1.5m/s^2$

Make Mass the subject

$Mass = \frac{2800N}{1.5m/s^2}$

$Mass = 1866.6667kg$

$Mass = 1867kg$ ---- approximated

Hence, the mass of the vehicle is 1867kg

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2 years ago

What is the y-intercept of the function, and what does this tell you about the car?

scZoUnD [109]

Write an equation in the standard form to represent the total rent (y) that Sam has to ... is the y-intercept of the function, and what does this tell you about the car?

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3 years ago