I NEED HELP WITH SOME PROBLEM ON BRAINLY PLEASE HELP

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IgorLugansk [536]

Answer:

Okay

Explanation:

4 0

3 years ago

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Ld' is the instruction with the longest latency on the CPU from Section 4.4 (in RISC-V text). If we modified ld and sd so that t

antiseptic1488 [7]

Answer:

See explaination

Explanation:

a)

The primary factors that influence the program's speed on a new CPU are given as:-

CPU Clock speed where the speed of the process instructions is being measured.

Multi-core which is when the transistors work faster than respective CPU.

Cache which helps to note that the transition of data is smooth and fast.

b)

So, there are two CPUs suppose the old one as 'A' and the modified one as 'B'.

'A' has following features---

It takes more time to execute program as it has more clock cycle time or we can say it has low clocking rate or low speed in terms of MHz or GHz. Clock rate is the inverse of Clock Cycle Time. When you will increase the clocking rate of CPU, it will get faster and then Clock Cycle Time will get reduced.

It has less instructions provided.

'B' has following features----

It takes less time to execute program as it has less clock cycle time or we can say it has high clocking rate or high speed in terms of MHz or GHz.

It has more instructions provided.

The performance of CPU depends upon 2 factors:

The number and types of instructions that are executed by the CPU

How fast the CPU can execute those instructions?

So, overall CPU B is better as it has less execution time than CPU A but the performance will always depend upon the number and type of instructions executed by the CPU so it may vary.

Please refer to attachment for instructions and formulas.

8 0

3 years ago

1. Explain the distinction between interpretation and compilation. What are the comparative advantages and disadvantages of the

serious [3.7K]

Answer:

11: Compiler translates a high level source program into a target equivalent (machine language).

An interpreter implements a virtual machine, the high-level programming language of which is the "machine language." The interpreter reads statements more or less one at a time in that language, and executes them as they go along.

12: One could also consider Java either. A compiler (complicated translator) can create code, which is then executed by a complicated virtual machine (interpreter)

13: A preprocessor is an initial translator which removes comments and white space, and group characters together into tokens such as keywords, identifiers, numbers, and symbols, as well as simple syntactic structure analyses. A compiler uses in-depth analysis and nontrivial transformation.

14: C++ implementations based on the early AT&T compiler created an intermediate program in C rather than assembly language

15: Stack-based language, similar to modern Java compiler byte code

16: A method in which a simple interpreter implementation evolves into building more complex versions until the compiler is built.

17: A compiler which translates byte code into machine language immediately prior to each program execution.

18: Lisp and Prolog

19: TEX and TROFF are one of such compilers that translate high-level document descriptions into laser printer or phototypesetter commands. Query language processors for database systems are also compilers that translate languages such as SQL into primitive file operations.

21: without havin to call multiple tools with command-line tools, You can write an entire program in an IDE.

8 0

3 years ago

1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s

konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0

3 years ago

Write a menu-based program in C++ for an input restricted dequeue using Linked List consist of

Natali5045456 [20]

Answer:

C++ With Examples

— Input-restricted Deque: In input-restricted, deletion can be done from ... getLast: Retrieves the last item in the queue. ... Now, we insert element 3 at the rear.

8 0

2 years ago