All categories

3 years ago

Which option organizes tasks based on importance?

Computers and Technology

1 answer:

crimeas [40]3 years ago

7 0

The correct answer is B. Prioritized view

Explanation:

The word "priority" is used to describe events, places, people, etc. that are considered of great importance. This means a task that is considered a priority is more important than regular tasks. In this way, in management software such as Outlook that allows users to monitor and manage tasks or things to do, users can organize tasks based on importance by clicking options such as "prioritized" or "prioritized view" that will display task from the most important to the least important. Thus, the option that organizes tasks based on importance is the prioritized view.

You might be interested in

Question 1. (50 points) 1.Write a program that computes information related to a sequence of entries regarding age of customers.

schepotkina [342]

Answer:

The solution code is written in Python 3:

count = 0
totalAge = 0
group1_count = 0 #age < 10
group2_count = 0 #age 10 - 20
group3_count = 0 #age 20 - 40
group4_count = 0 #age > 40
group1_total = 0 #subtotal age <= 10
group2_total = 0 #subtotal age 11 - 20
group3_total = 0 #subtotal age 21 - 40
group4_total = 0 #subtotal age > 40
age = int(input("Input an age: "))
youngest = age
oldest = age
while(age != -1):
count += 1
totalAge += age
if(age <= 10):
group1_count += 1
group1_total += age
elif(age <= 20):
group2_count += 1
group2_total += age
elif(age <= 40):
group3_count += 1
group3_total += age
else:
group4_count += 1
group4_total += age
if(youngest > age):
youngest = age
if(oldest < age):
oldest = age
age = int(input("Input an age: "))
totalCustomer = count
avgAge = totalAge / count
rangeAge = oldest - youngest
avgAgeGroup1 = group1_total / group1_count
avgAgeGroup2 = group2_total / group2_count
avgAgeGroup3 = group3_total / group3_count
avgAgeGroup4 = group4_total / group4_count
print("The total number of customers: " + str(totalCustomer))
print("Total number of customer in Group 1 (<=10): " + str(group1_count))
print("Total number of customer in Group 2 (11 - 20): " + str(group2_count))
print("Total number of customer in Group 3 (21 - 40): " + str(group3_count))
print("Total number of customer in Group 4 (> 40): " + str(group4_count))
print("Average age for all customer: " + str(avgAge))
print("Youngest age: " + str(youngest))
print("Oldest age: " + str(oldest))
print("The range of age: " + str(rangeAge))
print("Average age for group 1 (<=10): " + str(avgAgeGroup1))
print("Average age for group 2 (11 - 20): " + str(avgAgeGroup2))
print("Average age for group 3 (21 - 40): " + str(avgAgeGroup3))
print("Average age for group 4 (> 40): " + str(avgAgeGroup4))

Explanation:

Firstly, create the counter variables (e.g. count, group1_count, group2_count etc ) to track the total number of customer and number in each age group. Besides, create variables to hold the value of total of age and sub-total of each age group (Line 1 - 10). We presume there are only four age groups.

Next, prompt user to input the first age (Line 12)

Create variable youngest and oldest to track the lowest and highest age (Line 13 -14). At the moment, set the first input age as value of youngest and oldest.

Create a while loop with sentinel value -1 (Line 16). Within the loop, track the customer occurrence by incrementing counter variables by one (Line 17, 21, 24, 27 & 30). At the same time, add the current input age to totalAge and to group total (Line 18, 22, 25, 28, & 31).

If the current youngest value is bigger than the current input age, we set the current age to youngest (Line 33- 34).

If the current oldest value is smaller than the current input age, we set the current age to oldest (Line 36- 37).

After terminating the loop with -1, calculate the average age for all customers and for each age group and the range of age (Line 42- 48)

At last, display all the required calculation results using print function (50 - 62)

7 0

2 years ago

Explain four features of presentation packages

hichkok12 [17]

You have add more for anyone to be able to answer this, sorry

4 0

2 years ago

Scale-based classification for networks allows us to differentiate PANs, LANs, MANs, and WANs. Moreover, the structure of a netw

Nana76 [90]

Answer:

1. PANs uses Star Topology.

2. LAN uses four topology (Bus, Ring, Star and Tree).

3. MAN uses Star Topology.

4. WAN uses Bus topology.

Explanation:

1. PAN is the personnel area network, in which different personnel devices of a person are connect to each other with the help of the central computer with the help of Bluetooth, WiFi or some other medium. The central computer will work like a hub and all the devices are directly connected to the central PC. It is same as the ring topology where all the devices are connected to the central PC. So we can say that, PANs use star topology.

2. LAN is the local area network that has been established with in the premises of the organization. In this type of network, four typologies involve to complete the network connection. First is star topology, that is used to connect all the devices with the switches. Then Bus topology is used to connect all the switches with the single main cable. Ring topology is involved to connect all the switches with each other. Tree topology is used to connect different block if the organization in the form of branch to connect the central router or switch.

3. MAN is the Metropolitan Area Network which is comprise of different LANs. All the LANs are connected to the Router in the form of Star topology.

4. WAN is the wide area network. In WAN different MANs are connected to the network through single cable. This type of network uses Bus topology.

6 0

3 years ago

Answer the questions given below, share your ideas.Use the space for your answer.

Bess [88]

Answer:

I would get rid of the machine and well

8 0

2 years ago

Basic python coding, What is the output of this program? Assume the user enters 2, 5, and 10.

r-ruslan [8.4K]

Answer:

17.0

Explanation:

after first loop numA = 0.0 + 2 = 2.0

after second loop numA = 2.0 + 5 = 7.0

after third loop numA = 7 + 10 = 17.0

8 0

3 years ago