To know the exact amount of sodium hydroxide that the teacher needs to order, we need to know how many students are there and the amount that each student uses.
We will then multiply these two values and get the amount needed to be ordered.
Since you have not provided such data in your question, I will just assume them to show the steps of the solution. You can then apply these steps to the values you have.
Now, assume that a class of 60 students and that each student needs to use 130 grams of sodium hydroxide to use during the lab.
This means that the teacher will order:
130 x 60 = 7800 grams = 7.8 kg of sodium hydroxide
Answer:
The Kc of this reaction is 311.97
Explanation:
Step 1: Data given
Kp = 0.174
Temperature = 243 °C
Step 2: The balanced equation
N2(g) + 3H2(g) ⇌ 2NH3(g)
Step 3: Calculate Kc
Kp = Kc *(RT)^Δn
⇒ with Kp = 0.174
⇒ with Kc = TO BE DETERMINED
⇒ with R = the gas constant = 0.08206 Latm/Kmol
⇒ with T = the temperature = 243 °C = 516 K
⇒ with Δn = number of moles products - moles reactants 2 – (1 + 3) = -2
0.174 = Kc (0.08206*516)^-2
Kc = 311.97
The Kc of this reaction is 311.97
Answer: 15 grams of salt are there in 5 L of solution.
Explanation:
Concentration of a solution is defined as the number of grams of solute dissolved per liter of the solution.
Given : Concentration of solution : 3 g/L
1 Liter of solution contains = 3 gram of salt
Thus 5 L of solution contains = 
Thus 15 grams of salt are there in 5 L of solution.
