The ph of a solution is 3.7
Solution:
According to the equaiton of Henderson-Hasselback
pH= pKa+ log(salt/acid)
here it is given the value of
pKa= 4.7
So,
pH = pKa+ log(0.1/0.01)
= 4.7 + log(0.1)
= 4.7–1
= 3.7.
The following problem illustrates how the Henderson-Hasselbalch equation can be used to determine how much acid and conjugate base should be combined to create a buffer solution with a specific pH.
To learn more click the given link
brainly.com/question/13423434
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As the length of carbon chain increases the forces which hold the atoms also increases . Ethanol is a liquid due to higher bond energy
I would have to say B. Linear
I hope this helps!
Cheers, July.
Answer:
103.6°C
Explanation:
We solve this problem, with the Ideal Gases Law. We know that moles of gas are not changed through time.
P . V = n . R . T
So n (number of moles) and R (Ideal Gases constant) are the same, they are cancelled. In the two different states, we can propose:
P₁ . V₁ / T₁ = P₂ . V₂ /T₂
We need to make some conversions:
100 mL . 1 L/ 1000mL = 0.1L
500 kpa . 1atm / 101.3 kPa = 4.93 atm
300°C + 273 = 573 K
We replace data:
4.93 atm . 10L / T₂ = 750 atm . 0.1L / 573K
4.93 atm . 10L = (750 atm . 0.1L / 573K) . T₂
(4.93 atm . 10L) / (750 atm . 0.1L / 573K) → T₂
T₂ = 376.65 K
We convert K to °C → 376.65 K - 273 = 103.6 °C
Answer:
See explanation below
Explanation:
To get this, we need to apply the general expression for half life decay:
N = N₀e(-λt) (1)
Where:
N and N₀ would be the final and innitial quantities, in this case, masses.
t: time required to decay
λ: factor related to half life
From the above expression we need λ and t. To get λ we use the following expression:
λ = t₁₂/ln2 (2)
And we have the value of half life, so, replacing we have:
λ = 8.04 / ln2 = 11.6
Now, we can replace in (1) and then, solve for t:
0.75 = 40 exp(-11.6t)
0.75 / 40 = exp(-11.6t)
ln(0.01875) = -11.6t
-3.9766 = -11.6t
t = -3.9766 / -11.6
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t = 0.34 days</h2><h2>
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